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AnnyKZ [126]
2 years ago
10

Find the value of x. 6x+6 9x-9 32 24 x = [?]

Mathematics
1 answer:
Naddika [18.5K]2 years ago
6 0

Answer:

x=3

Step-by-step explanation:

\frac{6x+6}{32} =\frac{9x-9}{24}

Cross mutiply and x is equal to 3

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How much cardboard is needed to make the tissue box above? Square inches 8 3 3
Katen [24]

The amount of cardboard needed to make a cuboid box of dimensions 8 inch, 3 inches and 3 inches is 114 sq. inches.

<h3>What is the surface area of cuboid?</h3>

Let the three dimensions(height, length, width) be x, y,z units respectively.

The surface area of the cuboid is given by

S = 2(a\times b + b\times c + c\times a)

For this case, tissue box is almost cuboid shaped.

Also, its dimensions are given being 8 inches, 3 inches and 3 inches.

Suppose we measure the amount of cardboard needed in terms of area, then, the amount of cardboard needed to make that box(without any whole, full cuboid) is equal to the area of its surface(either outer or inner if we assume 0 inches thickness of cardboard),

Thus, we get:

Amount of cardboard needed = surface area of cuboid box with dimensions 8 by 3 by 3 (in inches)

= 2(8 \times 3 + 3 \times 3 + 3 \times 8) = 114 \: \rm in^2

Thus, the amount of cardboard needed to make a cuboid box of dimensions 8 inch, 3 inches and 3 inches is 114 sq. inches.

Learn more about surface area of cuboid here:

brainly.com/question/13522634

#SPJ1

5 0
2 years ago
Item 11
marysya [2.9K]

Answer:

4 ft higher

Step-by-step explanation:

Since the ladder is 10 ft long and its top is 6 feet high(above the ground), we find the distance of its base from the wall since these three (the ladder, wall and ground) form a right angled triangle. Let d be the distance from the wall to the ladder.

So, by Pythagoras' theorem,

10² = 6² + d²  (the length of the ladder is the hypotenuse side)

d² = 10² - 6²

d² = 100 - 36

d² = 64

d = √64

d = 8 ft

Since the ladder is moved so that the base of the ladder travels toward the wall twice the distance that the top of the ladder moves up.

Now, let x be the distance the top of the ladder is moved, the new height of top of the ladder is 6 + x. Since the base moves twice the distance the top of the ladder moves up, the new distance for our base is 8 - 2x(It reduces since it gets closer to the wall).

Now, applying Pythagoras' theorem to the ladder with these new lengths, we have

10² = (6 + x)² + (8 - 2x)²

Expanding the brackets, we have

100 = 36 + 12x + x² + 64 - 32x + 4x²

collecting like terms, we have

100 = 4x² + x² + 12x - 32x + 64 + 36

100 = 5x² - 20x + 100

Subtracting 100 from both sides, we have

100 - 100 = 5x² - 20x + 100 - 100

5x² - 20x = 0

Factorizing, we have

5x(x - 4) = 0

5x = 0 or x - 4 = 0

x = 0 or x = 4

The top of the ladder is thus 4 ft higher

7 0
2 years ago
The fractions 1/4,1/2,3/12 and are shown below
exis [7]

Answer:

the first one

Step-by-step explanation:

3 0
3 years ago
Plz help me. I need help fast
Margaret [11]
I think is C

Let me know!
5 0
3 years ago
The following image is a piece of tile from a kitchen floor. What does the bolded line represent?
prisoha [69]

Answer:

a line segment in the correct answer

6 0
3 years ago
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