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Setler79 [48]
3 years ago
15

PLS HELP Select the correct answer from each drop-down menu.

Computers and Technology
1 answer:
mote1985 [20]3 years ago
8 0

Answer:

i think its 5 then current

Explanation:

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Try my game? https://scratch.mit.edu/projects/589314237
Mama L [17]

Answer:

ok :)

Explanation:

3 0
3 years ago
Read 2 more answers
Which expression correctly determines that String s1 comes before String s2 in lexicographical order
Assoli18 [71]

Options :

A.) s1 < s2

B.) s1 <= s2

C.) s1.compareTo(s2) == −1

D.) s2.compareTo(s1) < 0

E.) s1.compareTo(s2) < 0

Answer: E.) s1.compareTo(s2) < 0

Explanation: Lexicographical ordering simply means the arrangement of strings based on the how the alphabets or letters of the strings appear. It could also be explained as the dictionary ordering principle of words based on the arrangement of the alphabets. In making lexicographical comparison between strings, the compareTo () method may be employed using the format below.

If first string = s1 ; second string = s2

To compare s1 with s2, the format is ;

s1.compareTo(s2) ;

If s1 comes first, that is, before s2, the method returns a negative value, that is a value less than 0 '< 0', which is the case in the question above.

If s2 comes first, that is, before s1, the method returns a positive value, that is a value greater than 0 '> 0'.

If both are s1 and s2 are the same, the output will be 0.

8 0
3 years ago
Scientists measure an object’s mass in kilograms and its weight in newtons. If you knowthe amount of mass of an object in kilogr
Phoenix [80]

Answer:

public class WeightCalculator {

   

   private static DecimalFormat df2 = new DecimalFormat("#.##");

   

   public static void main(String args[]){

       //create scanner to receive user input

       Scanner in = new Scanner(System.in);

       //alert user to input mass

       System.out. println("Enter the Mass in Kg");

       //collect the input as a string

       String s = in. nextLine();

       //convert string to double and multiply by 9.8

       Double weight = Double.valueOf(s)* 9.8;

       

       //Print out answer formatted to 2 decimal place

       System.out. println("The Weight is " + df2.format(weight) + "N");

       

       //conditional statement to check if weight is less than 100

       if (weight < 100){

           System.out. println("Oops, it is too light");

       }

       //conditional statement to check if weight is more than 500

       if (weight > 500){

           System.out. println("Oops, it is too heavy");

       }            

   }

}

7 0
4 years ago
16 POINTS
Nostrana [21]
It think it's a Nested List.
Im so sorry if this is wrong
6 0
3 years ago
Question # 4
bezimeni [28]

Answer:

the last one I think not 100% sure

6 0
4 years ago
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