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notsponge [240]
2 years ago
8

Evaluate lim x approaches to 2 : (sqrt(6-x)-2)/(sqrt(3-x)-1)

Mathematics
1 answer:
solong [7]2 years ago
5 0

Answer:

The answer is "0.5".

Step-by-step explanation:

Given:

\to \lim_{x\to 2}  \frac{(\sqrt{(6-x)}-2)}{(\sqrt{(3-x)}-1)}\\\\ \to \lim_{x\to 2}  \frac{\frac{d(\sqrt{(6-x)}-2)}{dx}}{\frac{(\sqrt{(3-x)}-1)}{dx}}\\\\

\to \lim_{x\to 2} \frac{\frac{-1}{2\sqrt{(6-x)} }}{\frac{-1}{2\sqrt{(3-x)}}}\\\\

\to \lim_{x\to 2} \frac{\sqrt{3-x}}{\sqrt{6-x}}\\\\ \to \frac{\sqrt{3-2}}{\sqrt{6-2}}\\\\ \to \frac{\sqrt{1}} {\sqrt{4}}\\\\ \to \frac{1}{2}\\\\ \to 0.5

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Simplify the imaginary number sqr -75
m_a_m_a [10]

Answer:

5i\sqrt{3}

Step-by-step explanation:

Using the rule of radicals

\sqrt{a} × \sqrt{b} ⇔ \sqrt{ab}

and \sqrt{-1} = i

Given

\sqrt{-75}

= \sqrt{25(3)(-1)}

= \sqrt{25}  × \sqrt{3} × \sqrt{-1}

= 5 × \sqrt{3} × i

= 5i\sqrt{3}

3 0
3 years ago
X = 7 + 3y
pogonyaev
<h3>Given Equation:</h3>

x = 7 + 3y

or, x - 3y - 7 = 0 ........ (i)

5x + 6y = 14

or, 5x + 6y - 14 = 0 .........(ii)

<h3>To Find:</h3>

The value of x and y.

<h3>Solution:</h3>

By dividing eq. ii by 2, we get

5/2x + 3y - 7 = 0 ........ (iii)

By adding eq. i and eq. iii, we get

15/2x = 0

or, <u>x = 0</u> ........(iv)

By putting eq.(iv) in eq. (i), we get

0 - 3y - 7 = 0

or, -3y = 7

or, <u>y = </u><u>-</u><u>7/</u><u>3</u>

<h2>Answer: ( 0, -7/3 )</h2>

The value of x and y is 0 and -7/3 respectively.

5 0
3 years ago
Read 2 more answers
How many solutions for x does the following equation have?
Luba_88 [7]
The answer would be D. Infinite
5 0
3 years ago
A contractor is installing tiles on a floor that measures 132 x 216 inches. If each tile measures 4 x 4 inches, how many tiles w
Kay [80]

Answer:

1782 tiles

Step-by-step explanation:

Given that:

Dimension fo floor = 132 x 216 inches

Area of floor = 132 * 216 = 28512 in²

Dimension of tiles = 4 * 4 inches

Area of tiles = 4 * 4 = 16 in²

Number of tiles needed to cover floor :

Area of floor / Area of tiles

28512 in² / 16 in²

= 1782 tiles

5 0
2 years ago
Plz help with math!!!!​
BigorU [14]

Answer:

The figure above is congruent by SSS axiom.

AB=DE (S)

AC=EF(S)

BC=DF(S)

Hence the given triangle are congrent.SSS axiom is Side.Side.Side axiom.

I think it will help you.

8 0
2 years ago
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