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notsponge [240]
2 years ago
8

Evaluate lim x approaches to 2 : (sqrt(6-x)-2)/(sqrt(3-x)-1)

Mathematics
1 answer:
solong [7]2 years ago
5 0

Answer:

The answer is "0.5".

Step-by-step explanation:

Given:

\to \lim_{x\to 2}  \frac{(\sqrt{(6-x)}-2)}{(\sqrt{(3-x)}-1)}\\\\ \to \lim_{x\to 2}  \frac{\frac{d(\sqrt{(6-x)}-2)}{dx}}{\frac{(\sqrt{(3-x)}-1)}{dx}}\\\\

\to \lim_{x\to 2} \frac{\frac{-1}{2\sqrt{(6-x)} }}{\frac{-1}{2\sqrt{(3-x)}}}\\\\

\to \lim_{x\to 2} \frac{\sqrt{3-x}}{\sqrt{6-x}}\\\\ \to \frac{\sqrt{3-2}}{\sqrt{6-2}}\\\\ \to \frac{\sqrt{1}} {\sqrt{4}}\\\\ \to \frac{1}{2}\\\\ \to 0.5

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Find the center and radius of the circle whose equation is x 2 + y 2 + 10x − 1
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we conclude that the center of the circle is the point (-5, 0).

<h3>How to find the center of the circle equation?</h3>

The equation of a circle with a center (a, b) and a radius R is given by:

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Here we are given the equation:

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If you want to learn more about circles:

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Step-by-step explanation:

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Answer:

19 1-point shots and 32 2-point shots

Step-by-step explanation:

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