Evaluate lim x approaches to 2 : (sqrt(6-x)-2)/(sqrt(3-x)-1)

Mathematics

1 answer:

solong [7]3 years ago

5 0

Answer:

The answer is "0.5".

Step-by-step explanation:

Given:

$\to \lim_{x\to 2} \frac{(\sqrt{(6-x)}-2)}{(\sqrt{(3-x)}-1)}\\\\ \to \lim_{x\to 2} \frac{\frac{d(\sqrt{(6-x)}-2)}{dx}}{\frac{(\sqrt{(3-x)}-1)}{dx}}\\\\$

$\to \lim_{x\to 2} \frac{\frac{-1}{2\sqrt{(6-x)} }}{\frac{-1}{2\sqrt{(3-x)}}}\\\\$

$\to \lim_{x\to 2} \frac{\sqrt{3-x}}{\sqrt{6-x}}\\\\ \to \frac{\sqrt{3-2}}{\sqrt{6-2}}\\\\ \to \frac{\sqrt{1}} {\sqrt{4}}\\\\ \to \frac{1}{2}\\\\ \to 0.5$

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Eli has saved $8 more than 1/3 of Angela's savings.If they each save $10 more Eli will have saved &4 more than Angela's savi

statuscvo [17]

Answer:

Eli has saved $10

Step-by-step explanation:

Let us use the first letters of their names to represent them.

A for Angela and E for ELi

So, from the first statement, we can write out an equation: E = $\frac{1}{3}$ A + 8, that is, one-third of Angela's savings + $8 will give us Eli's savings

From the second statement, we can write out: E + 10 = (A + 10) + 4 which means that if $10 is added to both their savings, Eli will still have $4 more than Angela.

So, we can solve both equations;

Equation 1: E = $\frac{1}{3}$ A + 8

Equation 2: E + 10 = (A + 10) + 4; which can be rewritten as E + 10 = A + 14

and then E = A + 4

The two equations (in bold), can then be solved simultaneously.

Let us carry out this operation to eliminate the E: Subtract equation 1 from equation 2, so that;

A + 4 - ( $\frac{1}{3}$ A + 8) = E - E

$\frac{2}{3}$ A - 4 = 0