Answer:
24.5
Step-by-step explanation:
20 + 140-50/20
= 20 + 4.5
=24.5
No Solution because x=5 is not a function y In terms of one variable
<span>f(x)=5x+3/6x+7
This means that f(6/x) = [</span>5(6/x)+3] / [6(6/x)+7] = [ 30/x +3 ] / [36/x +7]
If we assume x≠0 , f(6/x) = [30 +3x]/ [36 + 7x]
g(x)=√<span> [ x^2-4x ]
</span>
g(x-4) = √ [ (x-4)^2-4(x-4) ] = √ [ x² -8x +16 -4x +16 ] = √ [ x^2-12x +32]
Givens
AB + BC = AC
AB = 2(x + 1)
BC = 3x + 1
AC = 4(x + 2)
Substitute and Solve
AB + BC = AC
2(x + 1) + 3x + 1 = 4(x + 2) Remove the brackets on the left
2x + 2 + 3x + 1 = 4(x + 2) Collect the like terms on the left
5x + 3 = 4(x + 2) Remove the brackets on the right.
5x + 3 = 4x + 8 Subtract 4x from both sides.
5x - 4x + 3 = 8
x + 3 = 8 Subtract 3 from both sides
x =8 - 3
x = 5
Answers
AB=2(5 + 1) = 2 * 6 = 12
BC = 3x + 1 = 3*5 + 1 = 15 + 1 = 16
AC = 4(5 + 2) = 4*7 = 28