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mrs_skeptik [129]
2 years ago
15

A 1369.4 kg car is traveling at 28.9 m/s when the driver takes his foot off the gas pedal. It takes 5.1 s for the car to slow do

wn to 20 m/s. How large is the net force slowing the car
Physics
1 answer:
Darya [45]2 years ago
7 0

Answer:

F = 2389.603 N

Explanation:

Given:

Mass m = 1,369.4 kg

Initial velocity u = 28.9 m/s

Final velocity v = 20 m/s

Time t = 5.1 s

Find:

Net force

Computation:

a = (v - u)/t

a = (20 - 28.9)/5.1

a = -1.745 m/s²

F = ma

F = (1369.4)(1.745)

F = 2389.603 N

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A charged box ( m = 495 g, q = + 2.50 μ C ) is placed on a frictionless incline plane. Another charged box ( Q = + 75.0 μ C ) is
Rudik [331]

Answer:

a=16.2m/s^{2}

Explanation:

From the attached file diagram, the total force acting on the charged box is the downward weight and the repulsive force acting in opposite to the weight force . Hence we can write the total force as

F=masin\alpha -\frac{kQq}{r^{2}} \\\alpha =35^{0}, m=0.495kg, r=0.61m, Q=2.5*10^{-6}, q=75.0*10^{-6}\\

When fixed,F=o

Hence

masin\alpha =\frac{kQq}{r^{2}}\\0.495kg*asin35=\frac{9*10^{9}*2.5*10^{-6}*75.0*10^{-6}}{0.61^{2}} \\0.28a=4.5351\\a=\frac{4.5351}{0.28}\\\\ a=16.2m/s^{2}

The value of the acceleration is 16.2m/s^2

7 0
2 years ago
The law of universal gravitation (gravity) describes two factors that affect the force of gravity between objects. What two fact
kykrilka [37]
The force depends on the mass of both objects and the distance between them

F = G*m1*m2/r^2

So the force has a linear connection with the mass of both objects and a quadratic connection with the distance between the center of masses
4 0
2 years ago
A bicycle rider travels 50.0 km in 2.5 hours. What is the cyclists speed
krek1111 [17]
Hi,
Recall the formula V=d/t, where V stands for velocity or speed, d stands for distance and t stands for time. By substituting your values you get: V=50.0km/2.5h, which equals to 20km/h.
7 0
2 years ago
According to the law of conservation of mass, how would the masses compare?
Zarrin [17]

Explanation:

According to the law of conservation of mass, the masses at the start and finish of a reaction will stay the same. The law of conservation of mass "mass is always constant in a chemical reaction".

  • The law is the basis for chemical calculations.
  • Masses of reactants and products must be the same to show that mass is always conserved.
  • Disparity in the mass could result from loss of mass to the environment or some side reactions that cannot be easily monitored.

Learn more:

Law of conservation of mass brainly.com/question/5896850

#learnwithBrainly

4 0
3 years ago
When the temperature of 2.35 m^3 of a liquid is increased by 48.5 degrees Celsius, it expands by 0.0920 m^3. What is its coeffic
alexandr1967 [171]

Coefficient of volume expansion is 8.1 ×10⁻⁴ C⁻¹.

<u>Explanation:</u>

The volume expansion of a liquid is given by ΔV,

ΔV = α V₀ ΔT

ΔT = change in temperature  = 48.5° C

α =  coefficient of volume expansion =?

V₀ = initial volume = 2.35 m³

We need to find α , by plugin the given values in the equation and by rearranging the equation as,

\alpha=\frac{\Delta \mathrm{V}}{\mathrm{V}_{0} \Delta \mathrm{T}}=\frac{0.0920}{2.35 \times 48.5}=0.00081

  = 8.1 ×10⁻⁴ C⁻¹.

5 0
3 years ago
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