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2 years ago

As the temperature increases the number of effective collisions between reacting particles in a chemical reaction

1 answer:

8 0

Answer: option A) initially increases, then decreases.

Justification:

The increase of the rate of effective collisions among particles as the temperature increases is explained by the collision theory in virtue of the increase of the kinetic energy.

This is, as the temperature increase so the kinetic energy increase and the higher the kinetic energy the greater the number of collisions and the greater the chances that this energy overcome the activation energy (the energy needed to start the reaction).

Now, as the reaction progress the number of reactants particles naturally decrease (some of them have been converted into product) so this lower number of particles means lower concentration which means lower collisions and, thereafter, a decrease in the reaction rate.

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Answer:

i don’t know what kind of waves you mean but if you’re talking about sound waves...

Explanation:

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2 years ago

An object, with mass 83 kg and speed 15 m/s relative to an observer, explodes into two pieces, one 4 times as massive as the oth

Agata [3.3K]

Answer:

The amount of Kinetic energy added to the system is 2334.3J

Solution:

As per the question:

Mass of object, m = 83 kg

Relative velocity of the object, $v_{mb} = v_{m} - v_{o} = 15 m/s$

After the explosion,

mass of the fragment is M and the other fragment, M' = 4M

Velocity of the lighter fragment after collision, v = 0 m/s

Now,

Mass of heavier fragment, M' = $\frac{4}{5}m$

Mass of lighter fragment, M' = $\frac{1}{5}m$

Let the velocity of the heavier fragment be v'.

Therefore by the law of conservation of momentum, we have:

Momentum of the object before collision = Momentum of the object after collision

$mv_{mo} = Mv + M'v'$

$mv_{mo} = M.0 + \frac{4}{5}mv'$

$v' = \frac{5}{4}\times 15 = 18.75 m/s$

Now, the change in Kinetic Energy gives the amount of Kinetic energy added to the system:

$\Delta KE = KE_{final} - KE_{initial}$

$\Delta KE = \frac{1}{2}Mv'^{2} - \frac{1}{2}mv_{mo}^{2}$

Since, the lighter particle stops, it won't have any kinetic energy.

$\Delta KE = \frac{1}{2}\times \frac{4}{5}times 83\times {18.75}^{2} - \frac{1}{2}\times 83\times 15^{2}$

$\Delta KE = 11671.8 - 9337.5 = 2334.3 J$

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2 years ago

2 differences between calorimeter and thermometer ?

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Answer:

Calorimeter is used to measure heat in and represents that in units of joules per kelvin units J/˚C or kJ/K

A calorimeter is can be used to measure the amount of heat released or involved in a chemical reaction.

Whereas thermometer can only measures temperature or hotness of a substance. It cannot be used to measure the thermal rate or amount of heat energy of a reaction. Unit measurement used by thermometer is Celsius (°C).

Explanation:

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3 years ago

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harina [27]

The answer is C Hydroelectric

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3 years ago