Answer:
TERO BAU KO TAUKO MULA JEPAITE SODCHOS
Answer:
Step 2 contains error in the given problem.
Step-by-step explanation:
Given expression is:
Step 1: identifying the LCM.
The LCM identified is 6.
This step is correct.
In the next step, we multiply the LCM with each term of the equation.
Step 2:
However,
In the given solution, the LCM is not multiplied with each term.
Hence,
Step 2 contains error in the given problem.
Let's do this by Briot-Ruffini
First: Find the monomial root
x - 2 = 0
x = 2
Second: Allign this root with all the other coeficients from equation
Equation = -3x³ - 2x² - x - 2
Coeficients = -3, -2, -1, -2
2 | -3 -2 -1 -2
Copy the first coeficient
2 | -3 -2 -1 -2
-3
Multiply him by the root and sum with the next coeficient
2.(-3) = -6
-6 + (-2) = -8
2 | -3 -2 -1 -2
-3 -8
Do the same
2.(-8) = -16
-16 + (-1) = -17
2 | -3 -2 -1 -2
-3 -8 -17
The same,
2.(-17) = -34
-34 + (-2) = -36
2 | -3 -2 -1 -2
-3 -8 -17 -36
Now you just need to put the "x" after all these numbers with one exponent less, see
2 | -3x³ - 2x² - 1x - 2
-3x² - 8x - 17 -36
You may be asking what exponent -36 should be, and I say:
None or the monomial. He's like the rest of this division, so you can say:
(-3x³ - 2x² - x - 2)/(x - 2) = -3x² - 8x - 17 with rest -36 or you can say:
(-3x³ - 2x² - x - 2)/(x - 2) = -3x² - 8x - 17 - 36/(x - 2)
Just divide the rest by the monomial.
Answer:
7x-20=2x-3(3x+2)
We move all terms to the left:
7x-20-(2x-3(3x+2))=0
We calculate terms in parentheses: -(2x-3(3x+2)), so:
2x-3(3x+2)
We multiply parentheses
2x-9x-6
We add all the numbers together, and all the variables
-7x-6
Back to the equation:
-(-7x-6)
We get rid of parentheses
7x+7x+6-20=0
We add all the numbers together, and all the variables
14x-14=0
We move all terms containing x to the left, all other terms to the right
14x=14
x=14/14
x=1
Step-by-step explanation:
