What is the answer to y+5<9

Mathematics

1 answer:

attashe74 [19]2 years ago

8 0

Answer:

I think the answer would be y<4

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Racionalize o denominador da equação abaixo:<br> 5 + 3 ²√5 / ²√5

GrogVix [38]

I hope this helps

$\cfrac{5+3 \sqrt{5} }{ \sqrt{5} } =\cfrac{(5+3 \sqrt{5}) \sqrt{5} }{ \sqrt{5}* \sqrt{5} }= \cfrac{5 \sqrt{5}+15 }{5} = \cfrac{5 (\sqrt{5}+3) }{5} = \sqrt{5}+3$

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3 years ago

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earnstyle [38]

Answer:

Step-by-step explanation:

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2 years ago

What's the answer to my answer answer right ok thanks

Anika [276]

Feel free to ask any questions as to what I did

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3 years ago

In what instance would you use the upside down U when doing interval notation

Jet001 [13]

The U and inverted U symbols, ∪ and ∩, are mathematical symbols used to denote union or intersection, respectively. For example, when a rational algebraic equation is graphed, there may be some points where the equation is undefined. Visually, we see it as breaks or discontinuities. We use the ∪ symbol to express union. For example, {-∞,2)∪(4,+∞). That means that the graph passes at all x values except x=3.

The ∩ symbol is used for intersection of two lines, for instance. When equation A and equation B are graphed, they can intersect at points (x,y). It is therefore expressed as: A∩B = (x,y).

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2 years ago

Given: ABCD ∥gram, BK ⊥ AD , AB ⊥ BD AB=6, AK=3 Find: m∠A, BK, AABCD

jenyasd209 [6]

1. Consider right triangle ABK. The hypotenuse AB is 6 un. and the leg AK is 3 un. Since the leg is half of the hypotenuse, then the opposite to the leg angle is 30°. This means that m∠ABK=30°. Then m∠BAK=90°-30°=60°.

2. By the Pythagorean theorem,

$AB^2=AK^2+BK^2,\\\\6^2=3^2+BK^2,\\\\BK^2=36-9,\\\\BK^2=27,\\\\BK=3\sqrt{3}\ un.$

3. Consider right triangle ABD. In this triangle AD is hypotenuse and m∠ADB=90°-m∠BAD=90°-60°=30°. Then the leg AB opposite to the angle 30° is half of the hypotenuse and AD=12 un.

4. The area of parallelogram is

$A_{ABCD}=AD\cdot BK=12\cdot 3\sqrt{3}=36\sqrt{3}\ sq. un.$

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2 years ago