In the figure below, the two triangular faces of the prism are fight triangles with sides of length 3, 4, and 5. The other three
faces are rectangles. What is the surface area of the prism. 84 sq. units 96 sq. units 108 sq. units 72 sq. units
can someone please explain how to get the awnser...
can someone please explain how to get the awnser...
1 answer:
The figure of the prism is attached below.
The total surface area of the prism equals the sum of areas of two triangles and the three rectangles.
Surface Area of Prism = Area of 2 Triangles + Area of 3 Rectangles.
Area of a Triangle = 0.5 x Base x Height
Area of a Triangle = 0.5 x 3 x 4 = 6 square units
There are 3 rectangles. From the figure we can see that the bottom most rectangle has the dimensions 4 by 6. The left most rectangle has the dimensions 3 x 6 and the right most rectangle has the dimensions 5 by 6.
So, the Area of 3 rectangles will be = (4 x 6) + (3 x 6) + (5 x 6) = 72 square units
The Surface Area of the prism will be:
Surface Area = 2 (4) + 72 = 84 square units
Thus the correct answer is option A
The total surface area of the prism equals the sum of areas of two triangles and the three rectangles.
Surface Area of Prism = Area of 2 Triangles + Area of 3 Rectangles.
Area of a Triangle = 0.5 x Base x Height
Area of a Triangle = 0.5 x 3 x 4 = 6 square units
There are 3 rectangles. From the figure we can see that the bottom most rectangle has the dimensions 4 by 6. The left most rectangle has the dimensions 3 x 6 and the right most rectangle has the dimensions 5 by 6.
So, the Area of 3 rectangles will be = (4 x 6) + (3 x 6) + (5 x 6) = 72 square units
The Surface Area of the prism will be:
Surface Area = 2 (4) + 72 = 84 square units
Thus the correct answer is option A
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Answer:
<em>99.93%</em>
Step-by-step explanation:
<u>Probability of Independent Events</u>
Given the probability of success of each detector is 0.84 independently of the others, their combined success/failure probability can be computed with the product rule.
We can calculate the required probability by using the binomial distribution, but it's easier to calculate the probability of the negated event an subtract from 1.
We want to know the probability that a least one of the 4 systems detects the occurrence of theft. That probability is the sum of the probabilities that one of them, two of them, three of them or all of them succeed. The negated event is that NONE of them actually detects the theft. Being p the individual probability of success, p=0.84. Being q the probability of failure, q=0.16.
The probability that none of the systems detect the theft is
Thus, the probability that at least one of the systems detect the theft is
That means a 99.93%