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creativ13 [48]
3 years ago
7

a rectangle has a length of 12 and an unknown width x. write expression for the permeter and area of rectangle

Mathematics
1 answer:
svet-max [94.6K]3 years ago
7 0
If the width is literally x then:
12(2)+2(x)
24+2x is the perimeter

12(x)
12x is the area
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<img src="https://tex.z-dn.net/?f=%5Cfrac%7B3%2F7%7D%7B7%5Csqrt%7B10%7D%2F2%20%7D" id="TexFormula1" title="\frac{3/7}{7\sqrt{10}
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Multiply the numerator and denominator by 7×2 = 14 to eliminate the denominators of those fractions:

\dfrac{\dfrac37}{\dfrac{7\sqrt{10}}2}\times\dfrac{14}{14}=\dfrac{3\times2}{7\sqrt{10}\times7}=\dfrac6{49\sqrt{10}}

Rationalize the denominator by multiplying both numerator and denominator by √10:

\dfrac6{49\sqrt{10}}\times\dfrac{\sqrt{10}}{\sqrt{10}}=\dfrac{6\sqrt{10}}{49(\sqrt{10})^2}=\dfrac{6\sqrt{10}}{49\times10}=\dfrac{6\sqrt{10}}{490}

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\dfrac{6\sqrt{10}}{490}=\dfrac{3\sqrt{10}}{245}}

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