Answer:
60 pounds
Step-by-step explanation:
To find the adult weight, multiply 12 by 5.
Since 12 pounds is 20% of the adult weight, 100% of the adult weight would be 12 times 5.
12(5)
= 60
So, the adult weight of the puppy will be 60 pounds
Answer: Line 1: (2, 3) , (4, 12)
m = (12 - 3)/(4 - 2) = 9/2 This is the slope of the line
y = (9/2)x + b
3 = (9/2)(2) + b
3 = 9 + b
b = -6
y = (9/2)x - 6
Line 2: (5, 10) , (14,8)
m = (8 - 10)/(14 - 5) = -2/9
this slope is the opposite sign, and inverse of the first equation's slope. Therefore, the line is perpendicular.
y = mx + b
8 = (-2/9)(14) + b
8 = -28/9 + b
11.11 = b
y = (-2/9)x + 11.11
Step-by-step explanation: Hope this helps :)
Answer:
x= -1 and x =0
Step-by-step explanation:
all work is shown and pictured
Such a ray that divides an angle into two equal angles is called an angle bisector.
Likewise, two rays that divide an angle into three congruent angles are called angle trisectors. Figure %:
An angle bisected and trisected On the left, angle ABC is bisected by the ray BD.
Credits to google.
In short, no.
These are two questions and two answers.
1) Problem 17.
(i) Determine whether T is continuous at 6061.
For that you have to compute the value of T at 6061 and the lateral limits of T when x approaches 6061.
a) T(x) = 0.10x if 0 < x ≤ 6061
T (6061) = 0.10(6061) = 606.1
b) limit of Tx when x → 6061.
By the left the limit is the same value of T(x) calculated above.
By the right the limit is calculated using the definition of the function for the next stage: T(x) = 606.10 + 0.18 (x - 6061)
⇒ Limit of T(x) when x → 6061 from the right = 606.10 + 0.18 (6061 - 6061) = 606.10
Since both limits and the value of the function are the same, T is continuous at 6061.
(ii) Determine whether T is continuous at 32,473.
Same procedure.
a) Value at 32,473
T(32,473) = 606.10 + 0.18 (32,473 - 6061) = 5,360.26
b) Limit of T(x) when x → 32,473 from the right
Limit = 5360.26 + 0.26(x - 32,473) = 5360.26
Again, since the two limits and the value of the function have the same value the function is continuos at the x = 32,473.
(iii) If T had discontinuities, a tax payer that earns an amount very close to the discontinuity can easily approach its incomes to take andvantage of the part that results in lower tax.
2) Problem 18.
a) Statement Sk
You just need to replace n for k:
Sk = 1 + 4 + 7 + ... (3k - 2) = k(3k - 1) / 2
b) Statement S (k+1)
Replace
S(k+1) = 1 + 4 + 7 + ... (3k - 2) + [ 3 (k + 1) - 2 ] = (k+1) [ 3(k+1) - 1] / 2
Simplification:
1 + 4 + 7 + ... + 3k - 2+ 3k + 3 - 2] = (k + 1) (3k + 3 - 1)/2
k(3k - 1)/ 2 + (3k + 1) = (k + 1)(3k+2) / 2
Do the operations on the left side and you will find it can be simplified to k ( 3k +1) (3 k + 2) / 2.
With that you find that the left side equals the right side which is a proof of the validity of the statement by induction.
