George shouldn't think too far.
He should use the formula for Compound Interest.
Amount in compound interest, A = P(1+ r/100)ⁿ.
Where A = Amount, P = Principal, r is the rate per year, n = number of years.
Note: the expression (1+ r/100) is raised to power n.
From George's problem: P = 750, r = 22, I guess number of years , n = x
A(x) = 750( 1 + 22/100)ˣ
A(x) = 750( 1 + 0.22)ˣ
From your options I can't see an answer. Except the expression of option (A) is actually raised to power x, and not times x as stated in the option.
Answer:
the correct answer is two halves
Step-by-step explanation:
10/10 divided by 5 is 2/2
50%. students (in percent) who passed the second exam also passed the first exam.
Let's imagine that there are 100 kids in the teacher's class. We know that 40 of them passed BOTH tests, and 80 passed the second test.
Because if they weren't, they wouldn't have passed the first test and consequently wouldn't have passed both, we can be sure that the group of students who passed BOTH tests is only made up of the 80 who passed the second test.
Thus, both tests were passed by 40 of the 80 pupils who passed the second one:
40/80 = 1/2 = 50%.
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Answer:
B AND E
Step-by-step explanation:
hope that helpsndbwbe
Answer:
B
Step-by-step explanation:
