Yes I can be be a digital sketch pad
HOPE THIS HELPS!!!!!!!
Explanation:
African wild dogs are among the most effective predators in the world. They use extraordinary cooperation and teamwork to pursue, overhaul and bring down their prey.African wild dogs are struggling to cope with the rapid increase in human settlements and infrastructure development that are encroaching on their traditional range. They are perfectly adapted to their natural environment, but require vast territories to survive – much larger than most other carnivore species. This increased exposure to human contact poses numerous threats to the wild dogs’ survival.
If you have any questions revolving around this topic,feel free to ask me and I will be glad to help,Good luck!
Answer:
for (int i = 0; i < 9; ++i)
{
int k = 0;
while (k < 20 && scotus[i][k] != '')
{
cout << scotus[i][k];
k++;
}
cout << "\n";
}
Explanation:
scotus here is a two dimensional array. It contains names of 9 justices. so the loop starts from 0 and ends when i points to the last name element in the array. Then a while loop is used to check that name is longer than twenty characters and will keep on printing each output on the separate line.
Another way to write this:
for (int i = 0; i < 9; i++){
cout << scotus[i] << "\n";
}
This loop will keep on executing and printing the names of the nine justices at every iteration until it reaches the end of the array (last element of the array scotus).
IPSec
Hope that helps, Good luck!! (:
Answer:
A ) 200 Zombie systems
B ) 200 Zombie systems
Explanation:
maximum uplink data rate : 512 kbps = 512 * 1000 * 8 = 4096000 bits/sec
Determine the number of 512 byte ICMP echo packets = 512 * 8 = 4096 bits
hence the maximum number of 512-byte ICMP echo request (ping) packets a single zombie computer can send per second = 400 packets/sec
i.e. for 512kbps = 400 packets/sec
Determine the number of Zombie systems that the attacker will need to flood a target server
A) For a fast ethernet
A fast ethernet = 100 mbps
The number of Zombie systems needed = 1 zombie system * 200
and 1 zombie system = 512 kbps
therefore for a Fast ethernet the number of zombies systems needed = 200
B) For A Gigabit Ethernet
same as a fast ethernet system i.e. = 200
