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2 answers:
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Answer:
When we have a function f(x), the average rate of change in the interval (a, b) is:
In this case, we have the function:
f(x) = (x + 3)^2 - 2
(but we do not have the interval, and I couldn't find the complete question online)
So if for example, we have the interval (2, 4)
The average rate of change will be:
If instead, we want the rate of change in a differential dx around the value x, we need to differentiate the function (this is way more complex, so I will define some rules first).
Such that the rate of change, in this case, will be:
f'(x) = df/dx
For a function like:
g(x) = x^n + c
g'(x) = n*x^(n - 1)
And for:
h(x) = k( g(x))
h'(x) = k'(g(x))*g'(x)
So here we can write our function as:
f(x) = k(g(x)) = (x + 3)^2 - 2
where:
g(x) = x + 3
k(x) = x^2 - 2
Then:
f'(x) = 2*(x + 3)*1 = 2*x + 6
That is the rate of change as a function of x (but is not an "average" rate of change)
Answer:
y > -x -3
Step-by-step explanation:
The graph is shaded <em>above</em> the <em>dashed</em> line, indicating y-values in the solution are greater than those on the line, so your inequality will start with ...
y >
The y-intercept of the line is (0, -3), so the "b" value in ...
y > mx +b
will be -3.
The line has a rise of -3 for a run of 3 (between the marked points), so the slope is ...
m = rise/run = -3/3 = -1
Then the inequality you want is ...
y > -x -3
Answer:
x = 6/5 = 1
Step-by-step explanation:
3x + 1 = -2x + 7
+2x - 1 = + 2x - 1
5x = 6
x = 6/5 = 1
Hope this helps:)