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Inga [223]
3 years ago
15

5) PLEASE HELP WITH QUESTION. MARKING BRAINLIEST + POINTS GIVEN.

Mathematics
1 answer:
aev [14]3 years ago
5 0
Hello xD

I finally got this one right!

There is a formula to use in order to solve this thing, so find your notebook xD

The correct answer is option B

I really wish you the best and I'll keep trying my best to help you out!

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Best Answer Gets Brainliest Please help asap
FrozenT [24]
<h2>Answer:</h2>

[1] Area of base = 13 × 13 = 169in².

Area of faces = 4 (1/2 × 13 × 8) = 208in².

Surface area = (169 + 208)in² = 377in².

[2] Area of base = 1/2 × 5.2 × 4.5 = 11.7in².

Area of faces = 3 (√3/4 × 5.2²) = 35.1in².

Surface area = (35.1 + 11.7)in² = 46.8in².

[3] Area of base = 7 × 10 = 70in².

Area of faces = 2(1/2 × 7 × 6) + 2(1/2 × 10 × 4.8)

= 98in².

Surface area = (70 + 98)in² = 168in².

7 0
3 years ago
Point P lies on circle C, x^2+y^2=36. There are two unique tangents to circle D, x^2+y^2=18 that pass through point p. What is t
Anastasy [175]

Answer:

90°

Step-by-step explanation:

Circle C has radius √36 = 6

Circle D has radius √18 = 3√2

As the D radius intersecting either point of tangency, does so at a right angle.

The half angle θ between the tangents is

sinθ = 3√2 / 6 = ½√2

θ = 45°

so the angle between the tangents is 2(45) = 90°

6 0
3 years ago
Find the surface area of the right triangular prism (above) using its net (below). <br> units
8_murik_8 [283]

Answer:

120 units^2

Step-by-step explanation:

(12)(5)(0.5)(2) + (12)(2) + (13)(2) + (5)(2) = 120 units^2

6 0
3 years ago
If A= {a, b, c, d, e} and C= {c, d, e} then how are they equal
elena55 [62]
{c, d, e} is common to both sets A and C.

{c, d, e} is called "the intersection of A and C."

Look up "intersection (set theory)" on the 'Net, for more info.
8 0
3 years ago
Draw a right triangle with one leg value is 4 and the other leg value is 3. Use the triangle to find the exact values of the six
Nina [5.8K]

Step-by-step explanation:

Draw a right triangle with one leg value is 4 and the other leg value is 3

The triangle is attached below

To find hypotenuse , use Pythagorean theorem

c^{2} =a^{2} +b^{2} \\c^{2} =3^{2} +4^{2} \\\\c^{2} =25 \\\\c=\sqrt{25} =5

opposite side = 4, adjacent side =3 and hypotenuse = 5

Apply trigonometric ratios

sin(A)=\frac{opposite}{hypotenuse}=\frac{4}{5}

cos(A)=\frac{adjacent}{hypotenuse}=\frac{3}{5}

tan(A)=\frac{opposite}{adjacent}=\frac{4}{3}

cosec(A)=\frac{hypotenuse}{opposite}=\frac{5}{4}

sec(A)=\frac{hypotenuse}{adjacent}=\frac{5}{3}

cot(A)=\frac{adjacent}{opposite}=\frac{3}{4}

4 0
4 years ago
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