In the ΔIJH, the value of the cosec (I) is
.
Given ΔIJH the length of the hypotenuse is 65, the length of the base is 33, and the length of the opposite side is 56.
We have to find the value of the cosec (I).
A function of an arc or angle that is most easily represented in terms of the ratios of pairs of sides of a right-angled triangle, such as the sine, cosine, tangent, cotangent, secant, or cosecant.
We know cosec (I) = hypotenuse / opposite side
Substitute the values
cosec (I) = 65/56
= 
Hence the value of cosec (I) is
.
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Answer:
C
Step-by-step explanation:
just did it and got right
I think the answer is congruent
Answer:
104 Notepads per box
Step-by-step explanation:
b - boxes
416=4b
b=104
M + w = 253m + 4w = 90 Let's do substitution, first by solving the first equation for m. m = 25 - w Substitute! 3(25 - w) + 4w = 9075 - 3w + 4w = 90w = 15 m = 25 - 15 = 10 Hope this helps!