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Phoenix [80]
3 years ago
11

N(n - 4) + n(n + 8) = n(n - 13) + n(n + 1) + 16

Mathematics
2 answers:
Allushta [10]3 years ago
5 0
N^2 - 4n + n^2 + 8n = n^2 - 13n + n^2 + n + 16
-4n + 8n = -13n + n + 16
-4n = -12n + 16
4n + 12n = 16
16 = 16
n = 1
Margaret [11]3 years ago
3 0

Answer:

n = 1

Step-by-step explanation:

n(n - 4) + n(n + 8) = n(n - 13) + n(n+1) + 16

n^2 - 4n + n^2 + 8n = n^2 - 13n + n^2 + n + 16

n^4 + 4n = n^4 - 12n + 16

n^4 - n^4 + 4n + 12n - 16 = 0

16n - 16 = 0

16n = 16

n = 16/16

n = 1

better check this...

1(1 - 4) + 1(1 + 8) = 1(1 - 13) + 1(1 + 1) + 16

1(-3) + 1(9) = 1(-12) + 1(2) + 16

-3 + 9 = -12 + 2 + 16

6 = 4 + 2

6 = 6 (correct)...so it checks out

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Tanzania [10]

The quadratic equations and their solutions are;

9 ± √33 /4 = 2x² - 9x + 6.

4 ± √6 /2 = 2x² - 8x + 5.

9 ± √89 /4 = 2x² - 9x - 1.

4 ± √22 /2 = 2x² - 8x - 3.

Explanation:

Any quadratic equation of the form, ax² + bx + c = 0 can be solved using the formula x = -b ± √b² - 4ac / 2a. Here a, b, and c are the coefficients of the x², x, and the numeric term respectively.

We have to solve all of the five equations to be able to match the equations with their solutions.

2x² - 8x + 5, here a = 2, b = -8, c = 5.                                                  x = -b ± √b² - 4ac / 2a = -(-8) ± √(-8)² - 4(2)(5) / 2(2) = 8 ± √64 - 40/4.     24 can also be written as 4 × 6 and √4 = 2. So                                                                                     x = 8 ± 2√6 / 2×2= 4±√6/2.

2x² - 10x + 3, here a = 2, b = -10, c = 3.                                                   x =-b ± √b² - 4ac / 2a =-(-10) ± √(-10)² - 4(2)(3) / 2(4) = 10 ± √100 + 24/4. 124 can also be written as 4 × 31 and √4 = 2. So                                                                              x = 10 ± 2√31 / 2×2 = 5 ± √31 /2.

2x² - 8x - 3, here a = 2, b = -8, c = -3.                                                    x = -b ± √b² - 4ac / 2a = -(-8) ± √(-8)² - 4(2)(-3) / 2(2) = 8 ± √64 + 24/4.     88 can also be written as 4 × 22 and √4 = 2. So                                                                             x = 8 ± 2√22 / 2×2 = 4± √22/2.

2x² - 9x - 1, here a = 2, b = -9, c = -1.                                                     x = -b ± √b² - 4ac / 2a = -(-9) ± √(-9)² - 4(2)(-1) / 2(2) = 9 ± √81 + 8/4.                                          x = 9 ± √89 / 4.

2x² - 9x + 6, here a = 2, b = -9, c = 6.                                                    x = -b ± √b² - 4ac / 2a = -(-9) ± √(-9)² - 4(2)(6) / 2(2) = 9 ± √81 - 48/4.                                                                             x = 9 ± √33 / 4

To match we solve the monomials.

1. -15u^3 + 5u^3

Adding

-15u^3 + 5u^3=-10u^3

2.  10u^3 +(-5u^3)

Adding

10u^3-5u^3=5u^3

3. 10u^3 + 5u^3

Adding

10u^3 + 5u^3=15u^3

4.  5u^3+ (-10u^3)

Adding

5u^3-10u^3 =-5u^3

Two separate ways to find the answers.

7 0
2 years ago
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