Im not sure what it is but my best bet would be on A because the rest of them all say greater than 0 and you are trying to find the least.
Let x,y be two different numbers
suppose x^2=y^2
then x^2-y^2=0
which yields (x+y)(x-y)=0
so either x=y or x=-y
In any case, x and y must be the same value
also when a vairable is squared like y=x^2
we must note that there are 2 possible solutions
x=(+/-)sqrt(y)
Step-by-step explanation:
First, add or subtract both sides of the linear equation by the same number.
Secondly, multiply or divide both sides of the linear equation by the same number.
For a number to be rational by definition, a fractional representation of the number must exist.
So N = n/m is rational if n and m are integers.
Since it's given in fractional form it's rational by definition.
Hence false.
Answer:
was this supposed to be funny lol
Step-by-step explanation:
