0 is the y interception because that is where the line goes through on the graph
The solution to this problem is (-2,0). Your welcome, and yes im positive this is the correct answer.
By understanding and applying the characteristics of <em>piecewise</em> functions, the results are listed below:
- r (- 3) = 15
- r (- 1) = 11
- r (1) = - 7
- r (5) = 13
<h3>How to evaluate a piecewise function at given values</h3>
In this question we have a <em>piecewise</em> function formed by three expressions associated with three respective intervals. We need to evaluate the expression at a value of the <em>respective</em> interval:
<h3>r(- 3): </h3>
-3 ∈ (- ∞, -1]
r(- 3) = - 2 · (- 3) + 9
r (- 3) = 15
<h3>r(- 1):</h3>
-1 ∈ (- ∞, -1]
r(- 1) = - 2 · (- 1) + 9
r (- 1) = 11
<h3>r(1):</h3>
1 ∈ (-1, 5)
r(1) = 2 · 1² - 4 · 1 - 5
r (1) = - 7
<h3>r(5):</h3>
5 ∈ [5, + ∞)
r(5) = 4 · 5 - 7
r (5) = 13
By understanding and applying the characteristics of <em>piecewise</em> functions, the results are listed below:
- r (- 3) = 15
- r (- 1) = 11
- r (1) = - 7
- r (5) = 13
To learn more on piecewise functions: brainly.com/question/12561612
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Answer:
6
Step-by-step explanation:
17/3=5.67
since you can't have 0.67 sack. you just round it up to 6
5 : - 1/6 = 0.167 out of 10 = 1.67 out of 100 = 16.7
even number 0.33 out of 10:- 3.3 out of 100:- 33
a prime number 0.5 out of 10: 5 and out of 100:- 50
multipl of 3:- 0/33 out of 10:- 3.3 and out of 100: 33
