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grigory [225]
3 years ago
8

An investor has an account with stock from two different companies. Last year, his

Mathematics
2 answers:
m_a_m_a [10]3 years ago
4 0

Step-by-step explanation:10600

professor190 [17]3 years ago
3 0

Answer:

22.7%

Step-by-step explanation:

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Probabilities with possible states of nature: s1, s2, and s3. Suppose that you are given a decision situation with three possibl
amm1812

Answer:

1. P(s_1|I)=\frac{1}{11}

2. P(s_2|I)=\frac{8}{11}

3. P(s_3|I)=\frac{2}{11}

Step-by-step explanation:

Given information:

P(s_1)=0.1, P(s_2)=0.6, P(s_3)=0.3

P(I|s_1)=0.15,P(I|s_2)=0.2,P(I|s_3)=0.1

(1)

We need to find the value of P(s₁|I).

P(s_1|I)=\frac{P(I|s_1)P(s_1)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}

P(s_1|I)=\frac{(0.15)(0.1)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}

P(s_1|I)=\frac{0.015}{0.015+0.12+0.03}

P(s_1|I)=\frac{0.015}{0.165}

P(s_1|I)=\frac{1}{11}

Therefore the value of P(s₁|I) is \frac{1}{11}.

(2)

We need to find the value of P(s₂|I).

P(s_2|I)=\frac{P(I|s_2)P(s_2)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}

P(s_2|I)=\frac{(0.2)(0.6)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}

P(s_2|I)=\frac{0.12}{0.015+0.12+0.03}

P(s_2|I)=\frac{0.12}{0.165}

P(s_2|I)=\frac{8}{11}

Therefore the value of P(s₂|I) is \frac{8}{11}.

(3)

We need to find the value of P(s₃|I).

P(s_3|I)=\frac{P(I|s_3)P(s_3)}{P(I|s_1)P(s_1)+P(I|s_2)P(s_2)+P(I|s_3)P(s_3)}

P(s_3|I)=\frac{(0.1)(0.3)}{(0.15)(0.1)+(0.2)(0.6)+(0.1)(0.3)}

P(s_3|I)=\frac{0.03}{0.015+0.12+0.03}

P(s_3|I)=\frac{0.03}{0.165}

P(s_3|I)=\frac{2}{11}

Therefore the value of P(s₃|I) is \frac{2}{11}.

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3 years ago
Slope of (8,3) and (-4,3)
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Use the formula y2-y1/x2-x1.
3-3/-4-8
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The slope is 0, so the line is horizontal.
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2 years ago
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Answer:

72

Step-by-step explanation:

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2 years ago
The total length of pencils A, B and C is 29 cm. Pencil a is 11 cm shorter then pencil B, and pencil B is twice as long a pencil
satela [25.4K]

The length of pencil A is 5 cm

<em><u>Solution:</u></em>

Let the length of pencil A be "x"

Let the length of pencil B be "y"

Let the length of pencil C be "z"

<em><u>The total length of pencils A, B and C is 29 cm</u></em>

Therefore,

length of pencil A + length of pencil B + length of pencil C = 29

x + y + z = 29 ------------ eqn 1

<em><u>Pencil A is 11 cm shorter then pencil B</u></em>

x = y - 11 ------- eqn 2

<em><u>Pencil B is twice as long a pencil C</u></em>

y = 2z

z = \frac{y}{2} ------ eqn 3

<em><u>Substitute eqn 2 and eqn 3 in eqn 1</u></em>

y - 11 + y + \frac{y}{2} = 29\\\\2y + \frac{y}{2} = 29 + 11\\\\\frac{4y+y}{2} = 40\\\\5y = 80\\\\y = 16

<em><u>Substitute y = 16 in eqn 2</u></em>

x = 16 - 11

x = 5

Thus length of pencil A is 5 cm

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3 years ago
Perpendicular lines are defined as
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Lines that overlap each other opposite like a T or +
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