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4 years ago

Plot the points on your graph paper to answer the question.

1 answer:

5 0

TRUST ME THE CORRECT ANSWER IS: ARE NOT i put caps so you would see my answer lol but i just did the test and put are and i got it wrong! the correct answer is: are not :)

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Someone pls help!! :/

Flauer [41]

Answer:

104

Step-by-step explanation:

ok so to find the area of this triangle you need to use the number you have witch are 16 and 13 so we wana find the area of one side of the triangle witch it has mark ware it needs to be split and so 16 / 2 is 8 and so we have 2 pairs of 8 and now you multiply hight by width and get 8 x 13 is 104 so we devide that by two in order to get one section of the triandle so 104 / 2 is 52 and thats one side of the triangle and now we add 52 by 52 and get 104

6 0

3 years ago

Alright need answers for number 25-28 on This packet please reply To My question I posted

den301095 [7]

Q25 is D, Q26 is A, & Q28 is 6. Sorry, I'm not sure how to calculate Q27

5 0

3 years ago

Look at these two triangles.

xz_007 [3.2K]

If $U\hat{T}J = 100$ , all angles would be equal, resulting in similar triangles. So B is right

4 0

3 years ago

Find an equation of the plane with the given characteristics. The plane passes through the points (4, 3, 1) and (4, 1, -7) and i

Minchanka [31]

Answer:

$3x - 4y + z = 1$

Step-by-step explanation:

Given

$Point\ 1 = (4,3,1)$

$Point\ 2 = (4,1,-7)$

Perpendicular to $8x + 7y + 4z = 18$

Required

Determine the plane equation

The general equation of a plane is:

$a(x-x_1) + b(y - y_1) + c(z-z_1) = 0$

For $n =$

$(x_1,y_1,z_1) = (4,3,1)$

$(x_2,y_2,z_2) = (4,1,-7)$

First, we need to determine parallel vector $V_1$

$V_1 =$

$V_1$ is parallel to the required plane

From the question, the required plane is perpendicular to $8x + 7y + 4z = 18$

Next, we determine vector $V_2$

$V_2 =$

This implies that the required plane is parallel to $V_2$

Hence: $V_1$ and $V_2$ are parallel.

So, we can calculate the cross product $V_1 * V_2$

$V_1 =$

$V_2 =$

$n = V_1 * V_2$

$V_1 * V_2 =\left[\begin{array}{ccc}i&j&k\\0&2&8\\8&7&4\end{array}\right]$

The product is always of the form + - +

So:

$V_1 * V_2 = i\left[\begin{array}{cc}2&8\\7&4\end{array}\right]$ $-j\left[\begin{array}{cc}0&8\\8&4\end{array}\right]$ $+k\left[\begin{array}{cc}0&2\\8&7\end{array}\right]$