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IgorC [24]
2 years ago
12

I will give brainliest if someone can solve! Please help.

Mathematics
1 answer:
iVinArrow [24]2 years ago
8 0
The answer is very blurry I can’t see it
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What is -4 (-6x + 3) = 12
IgorC [24]

Answer: x = 1

Step-by-step explanation:

Simplifying

-4(-6x + 3) = 12

Reorder the terms:

-4(3 + -6x) = 12

(3 * -4 + -6x * -4) = 12

(-12 + 24x) = 12

Solving

-12 + 24x = 12

Solving for variable 'x'.

Move all terms containing x to the left, all other terms to the right.

Add '12' to each side of the equation.

-12 + 12 + 24x = 12 + 12

Combine like terms: -12 + 12 = 0

0 + 24x = 12 + 12

24x = 12 + 12

Combine like terms: 12 + 12 = 24

24x = 24

Divide each side by '24'.

x = 1

Simplifying

x = 1

6 0
2 years ago
Read 2 more answers
Jennifer works 3 1/2 hours each morning at the clinic. How many routine physicals could she complete in one morning? (Routine ph
den301095 [7]

Answer:

C

Step-by-step explanation:

Total Work hours = 3 1/2 hours

One routine physical routine requires: 1/3 hours.

Number of routines can be completed = Total work hours / Time required for one physical routine

= 3\frac{1}{2}  / \frac{1}{3}\\=\frac{7}{2} /\frac{1}{3} \\=\frac{7}{2} *3\\

= 10.5 routines.

In this case, we are unable to complete half a routine (0.5), so we will choose the highest possible whole number, in this case, its 10 routines.

5 0
2 years ago
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36= 2² x 3² how do i get the number to my prime factor
mojhsa [17]

Answer:

add up the exponents on each prime number

Step-by-step explanation:

2^2= 2x2

3^2=3x3

so 36=2^2x3^2=2x2x3x3

5 0
3 years ago
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Sandra has 1/2 of cup of sugar. She needs 3/4 of a cup of sugar to complete a recipe. What fraction of the required amount does
ValentinkaMS [17]
Example: Set up proportions.

3/4 cups → 1 batch
x cups → 2 batches

x = 2(3/4) = 6/4 = 1 1/2 cups

3/4 cups → 1 batch
y cups → 9 batches

y = 9(3/4) = 6 3/4 cups
7 0
2 years ago
Find the coordinates of the midpoint of a segment with the endpoints<br> (16,5) &amp; (28, -13)
BARSIC [14]
To determine the coordinates of the midpoints of a line segment, get the average of the both the abscissas and ordinates. In this example, the average of the abscissas is 22 and that of the ordinates is -4. Thus, the midpoint is (22, -4).
6 0
3 years ago
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