5

Can someone pls help solve this

Len [333]

Answer:

YOU JUST NEED T APPLY THE FORMULA OF CIRCLE AND IRREGULAR SQUARE AS TRAPEZOIID

Step-by-step explanation:

6 0

3 years ago

how many meatballs are required fora party of 10 adults and 5 childen? fomual is m=4a+2 where c= children and m=meatball and a=

professor190 [17]

The answer is 42 because there are 10 adults and
M=4(10)+2
M=40+2
M=42

3 0

4 years ago

The accompanying data on x = current density (mA/cm2) and y = rate of deposition (m/min)μ appeared in a recent study.

gtnhenbr [62]

Answer:

a) $r=\frac{4(333)-(200)(5.37)}{\sqrt{[4(12000) -(200)^2][4(9.3501) -(5.37)^2]}}=0.9857$

The correlation coefficient for this case is very near to 1 so then we can ensure that we have linear correlation between the two variables

b) $m=\frac{64.5}{2000}=0.03225$

Now we can find the means for x and y like this:

$\bar x= \frac{\sum x_i}{n}=\frac{200}{4}=50$

$\bar y= \frac{\sum y_i}{n}=\frac{5.37}{4}=1.3425$

$b=\bar y -m \bar x=1.3425-(0.03225*50)=-0.27$

So the line would be given by:

$y=0.3225 x -0.27$

Step-by-step explanation:

Part a

The correlation coeffcient is given by this formula:

$r=\frac{n(\sum xy)-(\sum x)(\sum y)}{\sqrt{[n\sum x^2 -(\sum x)^2][n\sum y^2 -(\sum y)^2]}}$

For our case we have this:

n=4 $\sum x = 200, \sum y = 5.37, \sum xy = 333, \sum x^2 =12000, \sum y^2 =9.3501$

$r=\frac{4(333)-(200)(5.37)}{\sqrt{[4(12000) -(200)^2][4(9.3501) -(5.37)^2]}}=0.9857$

The correlation coefficient for this case is very near to 1 so then we can ensure that we have linear correlation between the two variables

Part b

$m=\frac{S_{xy}}{S_{xx}}$

Where:

$S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i)}{n}$

$S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}$

With these we can find the sums:

$S_{xx}=\sum_{i=1}^n x^2_i -\frac{(\sum_{i=1}^n x_i)^2}{n}=12000-\frac{200^2}{4}=2000$

$S_{xy}=\sum_{i=1}^n x_i y_i -\frac{(\sum_{i=1}^n x_i)(\sum_{i=1}^n y_i){n}}=333-\frac{200*5.37}{4}=64.5$

And the slope would be:

$m=\frac{64.5}{2000}=0.03225$

Now we can find the means for x and y like this:

$\bar x= \frac{\sum x_i}{n}=\frac{200}{4}=50$

$\bar y= \frac{\sum y_i}{n}=\frac{5.37}{4}=1.3425$

And we can find the intercept using this:

$b=\bar y -m \bar x=1.3425-(0.03225*50)=-0.27$

So the line would be given by:

$y=0.3225 x -0.27$

4 0

3 years ago

Jason leaves Detroit at 2:00 PM and drives at a constant speed west along I-96. He passes Ann Arbor, 40 mi from Detroit, at 2:50

Vladimir [108]

Answer:

d = 48t will represent the distance 'd' traveled in 't' hours.

Step-by-step explanation:

Jason leaves Detroit at 2:00 PM and passes through Ann Arbor at 2:50 PM which is 40 mi distant from Detroit.

Speed during this journey was constant.

Jason traveled 40 mi in 50 minutes or $\frac{5}{6}$ hours from Detroit to Ann Arbor.

By the formula,

Speed = $\frac{\text{Distance traveled }}{\text{Time taken to travel this distance}}$

Speed = $\frac{40}{\frac{5}{6}}$

= 48 mi per hour

If he travels 'd' miles in 't' hours then by the formula of speed,

48 = $\frac{d}{t}$

d = 48t

7 0

3 years ago

Which value of k makes the inequality 11+2k>19 true?

Vadim26 [7]

Answer:

6.

Step-by-step explanation:

11 + 2k > 19

2k > 19 - 11

2k > 8

k > 8/2

k > 4.

4 0

3 years ago