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lutik1710 [3]
3 years ago
13

Polly buys 14 cupcakes for a party. The bakery puts them into boxes that hold 4 cupcakes each.

Mathematics
1 answer:
Temka [501]3 years ago
8 0

Answer:

Part a) The number of boxes needed will be 4

part b) The fraction of the box that is empty is \frac{1}{2}

Part c) Are needed 2 cupcakes to fill the last box

Step-by-step explanation:

Part a) How many boxes will be needed for Polly to bring all the cupcakes to the party?

To find out the number of boxes needed, divide the total number of cupcakes by 4 (maximum number of cupcakes that fit in each box).

so

\frac{14}{4}=3.5\ box

Round up

The number of boxes needed will be 4

Part b) If the bakery completely fills as many boxes as possible, what fraction of the last box is empty?

we know that

The maximum number of cupcakes per box is 4

The first three boxes have 4 cupcakes

The last box has

14-3(4)=2\ cupcakes

The fraction of the box that is empty is equal to the number of cupcakes missing to fill the box divided by the cupcake capacity of the box

\frac{2}{4}=\frac{1}{2}

Part c) How many more cupcakes are needed to fill this box

Subtract the number of cupcakes in the box from the cupcake capacity of the box

The last box has 2 cupcakes

The cupcake capacity of the box is 4

so

4-2=2\ cupcakes

therefore

Are needed 2 cupcakes to fill the last box

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If M is the centroid of triangle GHI, HL=45, JI=63, and KG=60, find the missing measures
AysviL [449]

Answer:

Part a) ML=15\ units

Part b) HM=30\ units

Part c) JM=21\ units

Part d) MI=42\ units

Part e) GM=40\ units

Part f) MK=20\ units

Step-by-step explanation:

see the attached figure to better understand the problem

we know that

A <u><em>centroid</em></u> of a triangle is the point where the three medians of the triangle meet. A median of a triangle is a line segment from one vertex to the mid point on the opposite side of the triangle.

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Part a) Find ML

we have

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we know that

ML=\frac{1}{3}HL

substitute the given value

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Part b) Find HM

we have

HL=45\ units

we know that

HM=\frac{2}{3}HL

substitute the given value

HM=\frac{2}{3}(45)

HM=30\ units

Part c) Find JM

we have

JI=63\ units

we know that

JM=\frac{1}{3}JI

substitute the given value

JM=\frac{1}{3}(63)

JM=21\ units

Part d) Find MI

we have

JI=63\ units

we know that

MI=\frac{2}{3}JI

substitute the given value

MI=\frac{2}{3}(63)

MI=42\ units

Part e) Find GM

we have

KG=60\ units

we know that

GM=\frac{2}{3}KG

substitute the given value

GM=\frac{2}{3}(60)

GM=40\ units

Part f) Find MK

we have

KG=60\ units

we know that

MK=\frac{1}{3}KG

substitute the given value

MK=\frac{1}{3}(60)

MK=20\ units

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