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trasher [3.6K]
3 years ago
7

Kris and Micky are running laps around the same track. Kris can run one lap in 8 minutes but Micky takes 12 minutes. If they bot

h start at the same place, the same time, and run in the same direction, at what time will they first pass each other?
Mathematics
1 answer:
Nat2105 [25]3 years ago
6 0

Answer:

4minutes,I think. that is the answer

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Can anyone solve this
andrew-mc [135]

Answer:

48976123456789109645

3 0
3 years ago
3x+y=8 I really don't understand this and I have tried to get the answer but always end up wrong.
Alecsey [184]

Answer:

The solution of the system of the equation is (2, 2)

Step-by-step explanation:

Let us solve the system of equations

∵ 3x + y = 8 ⇒ (1)

∵ 3x - y = 4 ⇒ (2)

→ Add equations (1) and (2) to eliminate y

∴ (3x + 3x) + (y + -y) = (8 + 4)

∴ 6x + 0 = 12

∴ 6x = 12

→ Divide both sides by 6 to find x

∵ \frac{6x}{6}=\frac{12}{6}

∴ x = 2

→ Substitute the value of x in equation (1) to find y

∵ 3(2) + y = 8

∴ 6 + y = 8

→ Subtract 6 from both sides

∵ 6 - 6 + y = 8 - 6

∴ y = 2

∴ The solution of the system of the equation is (2, 2)

7 0
3 years ago
At the beginning of year 1, Jonah invests $300 at an annual
olga55 [171]

At the beginning of year 6, that means 5 years only have elapsed, thus t = 5.

\bf ~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\\ P=\textit{original amount deposited}\dotfill &\$300\\ r=rate\to 4\%\to \frac{4}{100}\dotfill &0.04\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{annually, thus once} \end{array}\dotfill &1\\ t=years\dotfill &5 \end{cases} \\\\\\ A=300\left(1+\frac{0.04}{1}\right)^{1\cdot 5}\implies A=300(1.04)^5

6 0
4 years ago
On a mountain, the temperature decreases by 18°F every 5000 feet. What integer represents the change in temperature at 20,000 fe
gizmo_the_mogwai [7]
18 times 4 = 72

Because 5000 times 4 = 20,000

The change in temp. is -72degrees
8 0
3 years ago
PQ is a diameter of a circle with centre If angle PQR=55 ,SPR=25 and angle PQM=50
tigry1 [53]

Answer:

m∠QPR = 35°         m∠QPM =40°       m∠PRS = 30°

Step-by-step explanation:

ΔPRQ is a right triangle with right angle at R.  So m∠QPR = 90 - 55 = 35

ΔQPM is a right triangle with right angle at M.  So m∠QPM = 90 - 40 = 40

Arc RQ = 2(35) = 70 and arc SR = 2(25) = 50.  

So arc PS = 180 - (arc RQ + arc SR) = 180 - (70 + 50) = 180 - 120 = 60

Now arc PS is the intercepted arc for ∠PRS.  

Therefore, m∠PRS = 60/2 = 30

I used the fact that an inscribed angle has a measure 1/2 the measure of the intercepted arc several times.  Also, I used the fact that the acute angles of a right triangle are complementary.  And, finally I used the fact that an inscribed angle in a semicircle is a right angle.

I hope this helped.

5 0
3 years ago
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