Answer:
C. (3x)^2 - (2)^2
Step-by-step explanation:
Each of the two terms is a perfect square, so the factorization is that of the difference of squares. Rewriting the expression to ...
(3x)^2 - (2)^2
highlights the squares being differenced.
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We know the factoring of the difference of squares is ...
a^2 -b^2 = (a -b)(a +b)
so the above-suggested rewrite is useful for identifying 'a' and 'b'.
Answer:
Step-by-step explanation:
Use the power rule for differentiation.
Answer:
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
<u>Algebra I</u>
<u>Calculus</u>
Implicit Differentiation
The derivative of a constant is equal to 0
Basic Power Rule:
- f(x) = cxⁿ
- f’(x) = c·nxⁿ⁻¹
Product Rule:
Chain Rule:
Quotient Rule:
Step-by-step explanation:
<u>Step 1: Define</u>
-y - 2x³ = y²
Rate of change of tangent line at point (-1, -2)
<u>Step 2: Differentiate Pt. 1</u>
<em>Find 1st Derivative</em>
- Implicit Differentiation [Basic Power Rule]:
- [Algebra] Isolate <em>y'</em> terms:
- [Algebra] Factor <em>y'</em>:
- [Algebra] Isolate <em>y'</em>:
- [Algebra] Rewrite:
<u>Step 3: Differentiate Pt. 2</u>
<em>Find 2nd Derivative</em>
- Differentiate [Quotient Rule/Basic Power Rule]:
- [Derivative] Simplify:
- [Derivative] Back-Substitute <em>y'</em>:
- [Derivative] Simplify:
<u>Step 4: Find Slope at Given Point</u>
- [Algebra] Substitute in <em>x</em> and <em>y</em>:
- [Pre-Algebra] Exponents:
- [Pre-Algebra] Multiply:
- [Pre-Algebra] Add:
- [Pre-Algebra] Exponents:
- [Pre-Algebra] Divide:
- [Pre-Algebra] Add:
- [Pre-Algebra] Simplify:
Answer:
6
Step-by-step explanation:
a=1/2 b*h
a=1/2 3*4
a=1/2 12
a=6
:)