Answer:
Its degree can be at least 1970
Step-by-step explanation:
for each root of the form √q, where q is not a square, we have a root -√q. Therefore, we need to find, among the numbers below to 1000, how many sqaures there are.
Since √1000 = 31.6, we have a total of 30 squares:
2², 3², 4², ...., 30², 31²
Each square gives one root and the non squares (there are 1000-30 = 970 of them) gives 2 roots (one for them and one for the opposite). Hence the smallest degree a rational polynomial can have is
970*2 + 30 = 1970
Answer:
f(3x) - 2g(x+1) = 12x - 5
Step-by-step explanation:
You've got f[g(x)] and g[f(x)] correct
However, f(3x) means substitute 3x for x in f(x):
f(3x) = 2(3x) - 3
⇒ f(3x) = 6x - 3
2g(x+1) = 2[4 - 3(x + 1)]
⇒ 2g(x+1) = 2[4 - 3x -3]
⇒ 2g(x+1) = 2[1 - 3x]
⇒ 2g(x+1) = 2 - 6x
f(3x) - 2g(x+1) = (6x - 3) - (2 - 6x)
⇒ f(3x) - 2g(x+1) = 12x - 5
Answer:
(C) 19x+6^2+2
Step-by-step explanation:
Answer:
there is no question
Step-by-step explanation:
there is no question/angle so i don't know how to help you
