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8_murik_8 [283]
3 years ago
6

What is the answer to (−6)2

Mathematics
1 answer:
xxMikexx [17]3 years ago
8 0
Hi!
The answer is -12.
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Please show work and help me pls
Gekata [30.6K]

Answer:

The answer is 207.

Step-by-step explanation:

If you do 1 ÷ 3 you'd get 3. Then move on too the 1 in 3105. 1 ÷ 1 equals 1. You do that with the 0 and the 5 in 3105. The last step too do is is do the same thing with the 5 in 15. Such as, 5 ÷ 3, 5 ÷ 1, 5 ÷ 0, and lastly 5 ÷ 5. Now if you understand just divide the two numbers in 15, which are 1 and 5 to get the quotient in the division problem. Hope this helps, I'm not the greatest at explaining!

7 0
3 years ago
At a local coffee shop, three coffees and two muffins cost a total of $7.00. Two coffees and four
rewona [7]

Answer:

$10.25

Step-by-step explanation:

Set up a system of equations, so 3c + 2m = 7 and 2c + 4m = 8, where c = the cost of coffees, and m = cost of muffins

To solve multiply the first equation by -2(3c + 2m=7) so you get -6c -4m = -14 now add the two equations

-6c - 4m = -14

2c + 4m = 8   notice that -6c + 2c = -4c and -4m + 4m cancels, then -14+8=-6

so we have -4c = -6 so c = $1.50

To solve for m, substitute c = 1.50 so 3(1.50) + 2m = 7, so solve for m so

4.5 + 2m = 7, 2m = 2.5, so m = $1.25

So now solve the final problem 6(1.50) + 1(1.25) = $10.25

6 0
3 years ago
The Laplace Transform of a function f(t), which is defined for all t > 0, is denoted by L{f(t)} and is defined by the imprope
lesya692 [45]

(1) D

L_s\left\{t\right\} = \displaystyle\int_0^\infty te^{-st}\,\mathrm dt

Integrate by parts, taking

u = t \implies \mathrm du=\mathrm dt

\mathrm dv = e^{-st}\,\mathrm dt \implies v=-\dfrac1se^{-st}

Then

L_s\left\{t\right\} = \displaystyle \left[-\frac1ste^{-st}\right]\bigg|_{t=0}^{t\to\infty}+\frac1s\int_0^\infty e^{-st}\,\mathrm dt

L_s\left\{t\right\} = \displaystyle \frac1s\int_0^\infty e^{-st}\,\mathrm dt

L_s\left\{t\right\} = \displaystyle -\frac1{s^2}e^{-st}\bigg|_{t=0}^{t\to\infty}

L_s\left\{t\right\} = \displaystyle \boxed{\frac1{s^2}}

(2) A

L_s\left\{1\right\} = \displaystyle\int_0^\infty e^{-st}\,\mathrm dt

L_s\left\{1\right\} = \displaystyle\left[-\frac1se^{-st}\right]\bigg|_{t=0}^{t\to\infty}

L_s\left\{1\right\} = \displaystyle\boxed{\frac1s}

7 0
3 years ago
Plz can anyone help me?
Sati [7]

Answer:

400x

Step-by-step explanation:

as shown in the graph from points such as (1, 400) or (2,800) the person is traveling 400 per day

4 0
3 years ago
Find the area of the shaded region. Attached below
bonufazy [111]

Answer:16.56 cm


Step-by-step explanation:

5.8*1.2=6.96

6.4*.8=5.12

1.2+.8=2

5.6-2-3.6

5.6*.8=4.48

4.48+5.12+6.96=16.56

5 0
3 years ago
Read 2 more answers
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