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vagabundo [1.1K]
3 years ago
8

A car begins to depreciate at a rate of 24.9% annually as soon as it is driven off the lot. If a car was purchased for 26,500; h

ow much is it worth after the second year? The equation you used is? What is the value of the car after two years?
Mathematics
1 answer:
STatiana [176]3 years ago
6 0

Answer:

13197

Step-by-step explanation:

You have to do 24.9*2 and then find that percent of 26500

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30 divided by 2438 long division
Ksju [112]
The answer would be 81.3
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In the function y=5x^2-2, what effect does the number 5 have on the graph, as compared to the graph of y=x^2?
allochka39001 [22]

General Idea:

The Rules for Transformations of Functions are given below:

If f(x) is the original function, a > 0 and c > 0; Then

f(x)+k \; \; shift \; f(x) \; UPWARD \; k \; units\\\\f(x)-k \; \; shift \; f(x) \; DOWNWARD \; k \; units\\\\f(x+h) \; \; shift \; f(x) \; LEFT \; h \; units\\\\f(x-h) \; \; shift \; f(x) \; RIGHT \; h \; units\\\\-f(x) \; \; REFLECT \; f(x) \; in \; the \; x-axis\\\\f(-x) \; REFLECT \; f(x) \; in \; the \; y-axis\\\\a \cdot f(x), \; a>1 \; STRETCH \; f(x) \; vertically \; by \; a \; factor \; of \; a\\\\a \cdot f(x), \; 0

f(ax), \; a>1 \; SHRINK \; f(x) \; horizontally \; by \; a \; factor \; of \;\frac{1}{a}  .\\\\f(ax), \; 0

Applying the concept:

In the function y=5x^2-2, the effect that the number 5 have on the graph, as compared to the graph of y=x^2 is given below:

C.it stretches the graph vertically by a factor of 5

4 0
3 years ago
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Which graph shows the solution set of x^2+9x-22/x+4<_0
motikmotik

Answer:

The Tasty Beans Coffee House being planned for the corner of SE 12th and Main will ruin a perfectly nice neighborhood. Besides the fact that Tasty Beans already has coffee shops all over the city, it will pull business away from local coffee houses that have been here for decades. In addition, there is already a parking problem on that street, and the new business will just add to the congestion. They're planning a drive-up window, too, and that will mean a steady stream of traffic in a very high-volume area. Ask anyone walking down the street, and they'll tell you this is a bad idea. I speak for my whole neighborhood when I say, "Go away, Tasty Beans!"

Step-by-step explanation:

The Tasty Beans Coffee House being planned for the corner of SE 12th and Main will ruin a perfectly nice neighborhood. Besides the fact that Tasty Beans already has coffee shops all over the city, it will pull business away from local coffee houses that have been here for decades. In addition, there is already a parking problem on that street, and the new business will just add to the congestion. They're planning a drive-up window, too, and that will mean a steady stream of traffic in a very high-volume area. Ask anyone walking down the street, and they'll tell you this is a bad idea. I speak for my whole neighborhood when I say, "Go away, Tasty Beans!"

7 0
3 years ago
Which of the following trigonometric ratios are correct?
den301095 [7]

Hi there! In this problem, you should have the knowledge of three basic Trigonometric Ratio.

  • sinA = opposite/hypotenuse
  • cosA = adjacent/hypotenuse
  • tanA = opposite/adjacent

Now that we know three basic ratio. Let's check each choices!

  • sin50° = d/c

This choice is wrong because we focus on the 50° angle. When we focus on 50°, sin50° should be d/x and not d/c.

  • sin50° = c/x

This choice is also wrong because in ratio, it's cos50° that adjacent/hypotenuse.

  • tan50° = d/c

This choice is correct! As ratio states, tanA = opposite/adjacent.

  • tan50° = x/c

This choice is wrong. x/c is a reciprocal of cosine which is 1/cos. We call the reciprocal of cosine as secant or sec in short.

  • cos50° = x/d

This choice is wrong as x/d is a reciprocal of sine which is 1/sin. We call the reciprocal of sine as cosecant or cosec/csc in short.

  • cos50° = c/x

This choice is right by the ratio. Nothing really much to explain since we follow by ratio that is defined.

Answer

  • tan50° = d/c
  • cos50° = c/x

Questions can be asked through comment.

Furthermore, tan also has its reciprocal form itself which is called cotangent also known as cot in short.

Hope this helps, and Happy Learning! :)

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How do I find the area of a rhombus?
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A = pq/2
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q = diagonal 2


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