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3 years ago

Solve the formula for n. A=P sqrt2+n

Mathematics

1 answer:

jekas [21]3 years ago

6 0

Answer:

n = (A/P)² - 2

Step-by-step explanation:

I will assume that you meant A=P sqrt(2+n).

Squaring both sides, we get A² = P²(2 + n), or

2 + n = (A/P)²

Then n = (A/P)² - 2

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Question 10(Multiple Choice Worth 1 points)

dezoksy [38]

Step-by-step explanation:

Given that the set of data collected has an extreme value (24), a Median measure of center is more appropriate than a Mean measure.

We sort the same data collected in increasing order:

{0, 1, 2, 4, 4, 5, 5, 24}

There are 8 elements inside the set, so we check the 4th and 5th elements (closest to the center), which are 4 and 4.

Since they are equal, the Median is 4.

Our answer is Median; 4.

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3 years ago

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Solve for x. write both solutions. separated by a comma 7x^2+8x+1=0

oksano4ka [1.4K]

Answer:

look at the pic

Step-by-step explanation:

Simple trinomal

Glad to help!!!

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3 years ago

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Whats the answer to this equation 10-4=9-[]

V125BC [204]

We can write this expression as 10 - 4 = 9 - x

10 - 4 = 9 - x

6 = 9 - x

6 - 9 = 9 - x - 9

-3 = -x

-3/-1 = -x/-1

3 = x

Hope This Helped! Good Luck!

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3 years ago

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A pet store conducted a survey on the types of pets owned by the stores customers. construct a two-way table summarizing the dat

Inessa [10]

Answer:

$\begin{array}{cccc}&\text{Own cat}&\text{Do not own cat}&\text{Total}\\\text{Own dog}& 45 & 125 & 170\\\text{Do not own dog}& 78 & 52 & 130 \\\text{Total}& 123 & 177 &300\end{array}$

Step-by-step explanation:

From the table you can see that

45 customers own cat and dog;
78 own only cat, then 78+45=123 customers own cat;
125 own only dog, then 125+45=170 customers own dog;
52 own neither cat, nor dog;
78+45+125+52=300 customers in total;
300-123=177 customers do not own cat;
300-170=130 customers do not own dog.

Two-way table is

$\begin{array}{cccc}&\text{Own cat}&\text{Do not own cat}&\text{Total}\\\text{Own dog}& 45 & 125 & 170\\\text{Do not own dog}& 78 & 52 & 130 \\\text{Total}& 123 & 177 &300\end{array}$

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3 years ago

(adapted from Ross, 2.31) Three countries (the Land of Fire, the Land of Wind, and the Land of Earth) each make a 3 person team.

DaniilM [7]

Answer:

The answer is " $\frac{2}{9} \ and \ \frac{1}{9}$ "

Step-by-step explanation:

In point a:

The requires 1 genin, 1 chunin , and 1 jonin to shape a complete team but we all recognize that each nation's team is comprised of 1 genin, 1 chunin, and 1 jonin.

They can now pick 1 genin from a certain matter of national with the value:

$\frac{1}{\binom{3}{1}}=\frac{1}{3} .$

They can pick 1 Chunin form of the matter of national with the value:

$\frac{1}{\binom{3}{1}}=\frac{1}{3} .$

They have the option to pick 1 join from of the country team with such a probability: $\frac{1}{\binom{3}{1}}=\frac{1}{3}$

And we can make the country teams: $3! = 6$ different forms. Its chances of choosing a team full in the process described also are:

$6 \times \frac{1}{3}\times \frac{1}{3}\times \frac{1}{3}=\frac{2}{9}.$

In point b:

In this scenario, one of the 3 professional sides can either choose 3 genins or 3 chunines or 3 joniners. So, that we can form three groups that contain the same ninjas (either 3 genin or 3 chunin or 3 jonin).

Its likelihood that even a specific nation team ninja would be chosen is now: $\frac{1}{\binom{3}{1}}=\frac{1}{3}$

Its odds of choosing the same rank ninja in such a different country team are: $\frac{1}{\binom{3}{1}}=\frac{1}{3}$

The likelihood of choosing the same level Ninja from the residual matter of national is: $\frac{1}{\binom{3}{1}}=\frac{1}{3}$ Therefore, all 3 selected ninjas are likely the same grade: $3\times \frac{1}{3}\times \frac{1}{3}\times \frac{1}{3}=\frac{1}{9}$

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3 years ago

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