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vovikov84 [41]
3 years ago
14

Joslyn performed an experiment using a die with its faces numbered from 1 to 6. She rolled the die and recorded whether the 5 la

nded face up. She repeated the process many times and kept a cumulative record of the
total number of rolls and the total number of Ss landing face up. The following table shows part of her record.

Suppose Joslyn could roll the die 10.000 times and keep a record of the total number of Ss landing face up in the 10,000 rolls What would such a record Illustrate?
Mathematics
1 answer:
sasho [114]3 years ago
7 0

Answer:

The law of large numbers

Step-by-step explanation:

The Law of large numbers states that if we observe more and more reptitiions of any chance process, the proportion of times that a specific outcome occurs approaches a single value.

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Pedro has created the function f(x)= 4x-3/2 to represent the number of assingments he has completed where x represents the numbe
Law Incorporation [45]
The given function is
f(x) = 4x - 3/2
where
f(x) = number of assignments completed
x =  number of weeks required to complete the assignments

We want to find f⁻¹ (30) as an estimate of the number of weeks required to complete 30 assignments.
The procedure is as follows:

1. Set y = f(x)
   y = 4x - 3/2

2. Exchange x and y
   x = 4y - 3/2

3. Solve for y
   4y = x + 3/2
   y = (x +3/2)/4

4. Set y equal to f⁻¹ (x)
  f⁻¹ (x) = (x + 3/2)/4

5. Find f⁻¹ (30)
  f⁻¹ (30) = (30 + 3/2)/4 = 63/8 = 8 (approxmately)

Answer:
Pedro needs about 8 weeks to complete 30 assignments.

6 0
3 years ago
F(x) = (x + 3)(x + 5).
Kipish [7]

Answer:

Step-by-step explanation:

5 0
3 years ago
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Compute the second partial derivatives ∂2f ∂x2 , ∂2f ∂x ∂y , ∂2f ∂y ∂x , ∂2f ∂y2 for the following function. f(x, y) = 2xy (x2 +
blsea [12.9K]

Answer with step-by-step explanation:

We are given that a function

f(x,y)=2xy(x^2+y^2)^2

Differentiate partially w.r.t x

Then, we get

\frac{\delta f}{\delta x}=2y(x^2+y^2)^2+8x^2y(x^2+y^2)=(x^2+y^2)(2x^2y+2y^3+8x^2y)=2(5x^2y+y^3)(x^2+y^2)

Differentiate again w.r.t x

\frac{\delta^2f}{\delta x^2}=2(10xy)(x^2+y^2)+4x(5x^2y+y^3)=20x^3y+20xy^3+20x^3y+4xy^3=40x^3y+24xy^3

Differentiate function w.r.t y

\frac{\delta f}{\delta y}=2x(x^2+y^2)^2+2xy\times 2(x^2+y^2)\times 2y

\frac{\delta f}{\delta y}=(x^2+y^2)(2x^3+2xy^2+8xy^2)=2(x^2+y^2)(x^3+5xy^2)

Again differentiate w.r.t y

\frac{\delta^2f}{\delta x^2}=2(2y)(x^3+5xy^2)+20xy(x^2+y^2)=4x^3y+20xy^3+20x^3y+20xy^3=24x^3y+40xy^3

Differentiate partially w.r.t y

\frac{\delta^2f}{\delta y\delta x}=2(2y(5x^2y+y^3)+(x^2+y^2)(5x^2+3y^2))=10x^4+36x^2y^2+10y^4

\frac{\delta^2f}{\delta y\delta x}=10x^4+36x^2y^2+10y^4\frac{\delta^2f}{\delta x\delat y}=2(2x(x^3+5xy^2)+(3x^2+5y^2)(x^2+y^2))=10x^4+36x^2y^2+10y^4

\frac{\delta^2f}{\delta x\delat y}=10x^4+36x^2y^2+10y^4

Hence, if f(x,y) is of class C^2 (is twice continuously differentiable), then the mixed partial derivatives are equal.

i.e\frac{\delta^2f}{\delta y\delta x}=\frac{\delta^2f}{\delta x\delta y}

8 0
4 years ago
A backyard is 40.5 feet long and 25 feet wide. In order to install a pool, the yard needs to be reduced by a scale of 1/3. What
cestrela7 [59]

Answer:The area of the reduced backyard is 112.5 square feet

Step-by-step explanation:

The initial length of the backyard is 40.5 feet long.

The initial width of the backyard is 25 feet wide.

In order to install a pool, the yard needs to be reduced by a scale of 1/3. This means that the new length of the backyard is would be

40.5 × 1/3 = 40.5/3 feet lonng

The new width of the backyard would be

25 × 1/3 = 25/3 feet wide

The backyard is rectangular in shape. Area of a rectangle is length × width. The area of the reduced backyard becomes

40.5/3 × 25/3 = 1012.5/9 = 112.5 square feet

8 0
4 years ago
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What number rounds to 150 when rounded to the nearest ten
blagie [28]

Answer: well there a lot of answers

Step-by-step explanation:

so i got

145 146 147 148 149 150 151 152 153 154

7 0
3 years ago
Read 2 more answers
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