2 years ago

A point in Quadrant I has all negative values

Mathematics

1 answer:

Dima020 [189]2 years ago

8 0

Answer:

como????????????????

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What are all of the real roots of the following polynomial? f(x) x^4-24x^2-25

Greeley [361]

Answer:

x = ±5

Step-by-step explanation:

We are given the following polynomial function and we are to find all of its real roots:

$x^4-24x^2-25$

Let $y=x^2$ so we can now write it as:

$y^2-24y-25$

Factorizing it to get:

$(y^2+y)+(-25y-25)$

$y\left(y+1\right)-25\left(y+1\right)$

$\left ( y + 1 \right ) \left ( y - 2 5 \right)$

Substitute back $y=x^2$ to get:

$\left ( x^2 + 1 \right ) \left ( x^2 - 25 \right )$

$\left ( x^2 + 1 \right ) \left ( x + 5 \right ) \left ( x - 5 \right )$

The quadratic factor has only complex roots. Therefore, the real roots are x = ±5.

3 0

3 years ago

Read 2 more answers

Can you see the specific pattern they follow? (2,4,6,8...)(3,6,12,24...)( 5,10,15,20,...)

mars1129 [50]

They times each number by 2

8 0

2 years ago

Can anybody help me?

Kruka [31]

f(-2) = 2(-2)² - 8(-2) + 6 = 30

f(-1) = 2(-1)² - 8(-1) + 6 = 16

f(0) = 2(0)² - 8(0) + 6 = 6

f(1) = 2(1)² - 8(1) + 6 = 0

f(2) = 2(2)² - 8(2) + 6 = -2

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2 years ago

Can I get help wit my second question

marishachu [46]

The answer is 1.8 :)

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How do you expressed the difference in the measures of center as a multiple of the measure of variation in a box plot when the I

pishuonlain [190]

You just use a calculator

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