1) n(6;1;-1)=n(A;B;C), point A(2;9;4)=A(x₀;y₀;z₀);
2) common view for a plane according the conditions is: A(x-x₀)+B(y-y₀)+C(z-z₀)=0;
3) after substituted coordinates: 6(x-2)+(y-9)-(z-4)=0; ⇒ 6x+y-z-17=0.
Answer:
530 in ^2
Step-by-step explanation:
The figure given is a triangle
We use the formula for the area of a triangle
A = 1/2 bh where b is the length of the base and h is the height
The height is perpendicular to the base( at 90 degrees)
A = 1/2 ( 26.5) * ( 40)
= 530 in ^2
3/24 would be down to 1/8 so 3/24 is smaller
The Solution:
Given:
We are required to find the area of the sector GPH.
The formula for the area of sector GPH is:

Substitute these values in the formula.

Therefore, the correct answer is:
Answer:
817.71
Step-by-step explanation:
Hi!
This involves applying trigonometry.
Because we are trying to figure out the height of Burj Khalifa, we are trying to find the length of AB. We already have CB, which is the adjacent side with respect to the angle. Then, AB would be the opposite side with respect to the angle given.
Remember SOH CAH TOA? Well, we have the adjacent and opposite sides involved in this, so we use the tangent function!
It will be as follows:
tan(73) = AB / 250
AB = (250)(tan(73))
AB = 817.71 meters