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Akimi4 [234]
3 years ago
14

In the first event, the eighth graders are running a baton relay race with three other classmates. The teams top speed for each

leg is 56.8 one seconds, 59.22 seconds, 57.39 seconds, and 60.11 seconds. Use the information to protect his teams best time for the race. Each leg of the race from part a is the same distance. Calculate the teams average time for each leg of the race. Show your work
Mathematics
1 answer:
chubhunter [2.5K]3 years ago
8 0

Answer:

The best time is 56.81 seconds

Average leg time is 58.3825 seconds

Step-by-step explanation:

Here, we want to start by stating the team’s best time for the race

The team’s best time for the race is the smallest time spent on a lap

From the times given, the best time is 56.81 seconds

Now, we want to calculate the average time

We simply add up all these and divide by count

Mathematically, that will be;

(56.81 + 59.22 + 57.39 + 60.11)/4 = 58.3825 seconds

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P varies directly with the square of R. When R is 4, P is 56. Find the value of P when R is 6
Sav [38]
Hey!
The formula of direct variation is y = kx. So we know that p = kr^2
Hint: after it says varies, it's basically the equal sign. 
so we can set it up
56 = 4^2k
56=16k
now we want k alone so we have to divide 16 on both sides
k=3.5
We can now solve for p like it asks
p = 3.5*6^2
p=126
There's your answer!
Hope this helps!
6 0
3 years ago
A box contains 15 resistors. twelve of them are labelled 50ω and the other three are labeled 100ω. what is the probability that
Igoryamba

Answer : P(second resistor is 100ω , given that the first resistor is 50ω) is given by

\frac{1}{5}

Explanation :

Since we have given that

Total number of resistors =15

Number of resistors labelled with 50ω = 12

Number of resistors labelled with 100ω =3

Let A: Event getting resistor with 50ω

B: Event getting resistor with 100ω

Since A and B are independent events .

So,

P(A\cap B)=P(A).P(B)

Now, According to question , we can get that

P(A)= \frac{12}{15}=\frac{4}{5}\\\\P(B)=\frac{3}{15}=\frac{1}{5}

So,

P(A\cap B)=P(A).P(B)\\\\P(A\cap B)=\frac{4}{5}\times \frac{1}{5}\\\\P(A\cap B)=\frac{4}{25}

So, by using the conditional probability , which state that

P(B\mid A)=\frac{P(A\cap B)}{P(A)}

P(B\mid A)=\frac{\frac{4}{25}}{\frac{4}{5}}\\\\P(B\mid A)=\frac{5}{25}\\\\P(B\mid A)=\frac{1}{5}

So, P(second resistor is 100ω , given that the first resistor is 50ω) is given by

\frac{1}{5}


4 0
4 years ago
Please help!!! I’ll mark you as brainliest!!!
Sedaia [141]
Ok I’ll break this down so it’s easier to understand:

So you start of with $80

The first step is to find 20% off

An easy way to find 20% is to divide it by 5.

80/5= 16

And since it’s 20% OFF we subtract 16 from 80

80-16= 64

Next we need to do the coupon

It is $5 off so

64-5= 59

And finally the rebate which is $2

59-2= 57

Answer:
57
3 0
3 years ago
Read 2 more answers
What is the value of x?
eimsori [14]

Answer:

16.1

Step-by-step explanation:

7 0
3 years ago
GOD BLESS YOU!!!!!!!!!!!!!!!!<br><br>​
Gnom [1K]

Answer:

GOD BLESS YOU TOO!!!

Step-by-step explanation:

3 0
3 years ago
Read 2 more answers
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