X=5
Y=8
Z=8
3x+2y-z=23 --> z=-23+2y+3x
Y=8
Substitute for -2y+4z=16
-2(8)+4(-23+2(8)+3x)=16
-16-28+12x=16
-44+12x=16
12x=60
X=5
Substitute known y and x values into z=-23+2y+3x
Z=-23+2(8)+3(5)
Z=-23+16+15
Z=8
Answer:
<u>P(three tails) = 27/125 or 21.6%</u>
<u>P(two tails followed by one head) = 18/125 or 14.4%.</u>
Step-by-step explanation:
1. Let's review the information provided to us to answer the questions correctly:
Probability of getting a head when a biased coin is tossed = 2/5
therefore,
Probability of getting a tails when a biased coin is tossed = 3/5
2. Find the following probabilities and select the correct solution.
P(three tails) =
3/5 * 3/5 * 3/5 = 27/125 or 21.6%
P(two tails followed by one head) =
3/5 * 3/5 * 2/5 = 18/125 or 14.4%.
Step 1: 1
(((x3) - (2•5x2)) + 29x) - 30 = 0
Step 2 2.1 x3-10x2+29x-30 is not a perfect cube
Step 3 Factoring: x3-10x2+29x-30
Thoughtfully split the expression at hand into groups, each group having two terms :
Group 1: 29x-30
Group 2: -10x2+x3
Pull out from each group separately :
Group 1: (29x-30) • (1)
Group 2: (x-10) • (x2)
It is upside down, can't see it properly!