343^1/3
=(7)^3*1/3 [ 3 and 3 are cancelled]
=7
X - 3pt baskets (he reaches 3x points)
y - 2pt baskets (he reaches 2y points)
We know, that y=x+43
97 - 1 free throw = 97 - 1 = 96
Sum of points: 96
3x + 2y = 96. Substitute to "y" an expression "x+43" :
3x + 2(x+43)=96
3x+2x+86=96
5x=10 |:5
x=2
So y=x+43=2+43=45
He has made 2 three points baskets and 45 two points baskets
I think answer is b that is 10raise to 2
Answer:
For first lamp ; The resultant probability is 0.703
For both lamps; The resultant probability is 0.3614
Step-by-step explanation:
Let X be the lifetime hours of two bulbs
X∼exp(1/1400)
f(x)=1/1400e−1/1400x
P(X<x)=1−e−1/1400x
X∼exp(1/1400)
f(x)=1/1400 e−1/1400x
P(X<x)=1−e−1/1400x
The probability that both of the lamp bulbs fail within 1700 hours is calculated below,
P(X≤1700)=1−e−1/1400×1700
=1−e−1.21=0.703
The resultant probability is 0.703
Let Y be a lifetime of another lamp two bulbs
Then the Z = X + Y will follow gamma distribution that is,
X+Y=Z∼gamma(2,1/1400)
2λZ∼
X+Y=Z∼gamma(2,1/1400)
2λZ∼χ2α2
The probability that both of the lamp bulbs fail within a total of 1700 hours is calculated below,
P(Z≤1700)=P(1/700Z≤1.67)=
P(χ24≤1.67)=0.3614
The resultant probability is 0.3614
