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11Alexandr11 [23.1K]
3 years ago
8

A tourist in France wants to visit 8 different cities. If the route is randomly selected, what is the probability that she will

visit the cities in alphabetical order?
Mathematics
2 answers:
Harlamova29_29 [7]3 years ago
7 0

Answer:

Probability p( selecting 8 cities alphabetically) = 2.48×10^-5

Step-by-step explanation:

Number of possible ways of choosing 8 cities=Permutation P(n,k) = n!/(n-k)!

P(8,8)= 8!/(8-8)! = 8! = 40,320

Probability (selecting 8 cities alphabetically) = 1/40320 = 2.48×10^-5

Shkiper50 [21]3 years ago
7 0

Answer:

<em>The answer is 0.00002480</em>

Step-by-step explanation:

From the question stated let us recall the following statement.

The number of cities the tourist wants to visit is =8

Now,

If the route is selected randomly, what is the probability that the cities she visits are in alphabetical order.

Therefore,

The probability that she visits the cities in alphabetical order = 1/8!

There are 8! = 40320 ways in which these cities can be visited

P(Visiting in alphabetical order) = 1/40320 = 0.00002480

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kipiarov [429]

Hello from MrBillDoesMath!

Answer:

225

Discussion:

Sum ( 2n - 1)                  from  n = 1 to 15              

= Sum(2n) - Sum(1)        from n = 1 to 15

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Thank you,

MrB

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