Question

A tourist in France wants to visit 8 different cities. If the route is randomly selected, what is the probability that she will visit the cities in alphabetical order?

Answer 1

Answer:

Probability p( selecting 8 cities alphabetically) = 2.48×10^-5

Step-by-step explanation:

Number of possible ways of choosing 8 cities=Permutation P(n,k) = n!/(n-k)!

P(8,8)= 8!/(8-8)! = 8! = 40,320

Probability (selecting 8 cities alphabetically) = 1/40320 = 2.48×10^-5

Answer 2

Answer:

The answer is 0.00002480

Step-by-step explanation:

From the question stated let us recall the following statement.

The number of cities the tourist wants to visit is =8

Now,

If the route is selected randomly, what is the probability that the cities she visits are in alphabetical order.

Therefore,

The probability that she visits the cities in alphabetical order = 1/8!

There are 8! = 40320 ways in which these cities can be visited

P(Visiting in alphabetical order) = 1/40320 = 0.00002480