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Naya [18.7K]
3 years ago
11

Use point-slope form, y - y1 = m(x - x1), to find the linear equation of a line that passes through the points (2, -1) and (10,

7).
Mathematics
2 answers:
arsen [322]3 years ago
7 0
Slope: 7 - - 1 divided by 10-2 = 1
y+1 = 1(x - 2)
y + 1 = x - 2
NNADVOKAT [17]3 years ago
5 0

Answer:

y =  ✔ 1 x +  ✔ -3

Step-by-step explanation:

edge 2020!

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Multiply equation II by 2 and then add up the equations.
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3-4/5X-2/3–3/15+3/5divided by -3/2
deff fn [24]

Answer:

-2(6x-13)/15

Step-by-step explanation:

This is done by simplifying the expression as well as combining like terms

4 0
3 years ago
A circle is centered at the point (5, -4) and passes through the point (-3, 2).
zepelin [54]

Answer:

(x-5)^2+(y+4)^2=100

Step-by-step explanation:

As we know the given points

Center = (5, -4)

and

Point on circle = (-3,2)

The distance between point on circle and center will give us the radius of circle

So,

The formula for distance is:

\sqrt{(x_{2}-x_{1} )^{2}+(y_{2}-y_{1})^{2}}\\Taking\ center\ as\ point\ 1\ and\ the\ other\ point\ as\ point\ 2\\d=\sqrt{(-3-5)^{2}+(2-(-4))^{2}}\\d=\sqrt{(-8)^{2}+(2+4)^{2}}\\d=\sqrt{(-8)^{2}+(6)^{2}}\\\\d=\sqrt{64+36}\\d=\sqrt{100} \\ d=10\\So\ the\ radius\ is\ 10

The standard form of equation of circle is:

(x-h)^{2}+(y-k)^{2}=r^{2}

where h and k are the coordinates of the center. So putting in the value:

(x-5)^{2}+(y-(-4))^{2}=(10)^{2}\\(x-5)^{2}+(y+4)^{2}=100

8 0
3 years ago
A book had a length of 5 inches and a width of 10 inches what is the area of the book
jeka94
50ft squared
{50}^{2}
3 0
4 years ago
A cake has circumference of 25 1/7 inches. What is the area of the cake? Use 22/7 to approximate π. Round to the nearest hundred
choli [55]

Answer:

50.29 in^2

Step-by-step explanation:

From the circumference we need to find the radius.

Since C = 2*pi*r, r = C / (2*pi).

Here, with C = 25  1/7 in, r = (25  1/7 in) / [ 2(22/7) ], or r = 4 in

The area of the cake is A = pi*r^2, or (here)  A = (22/7)(4 in)^2 = 50.29 in^2

5 0
3 years ago
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