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GalinKa [24]
2 years ago
9

What is the variable equal to? t • 7 = 63 t = 12 t = 8 t = 9 t = 441

Mathematics
1 answer:
iVinArrow [24]2 years ago
8 0

Answer:

The variable t is equal to 9.

Step-by-step explanation:

We are given t • 7 = 63.  To solve this for t, we divide both sides of this equation by 7, obtaining:

t = 63/7 = 9

The variable t is equal to 9.

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If the dimensions of a triangle are cut in half, then the new perimeter is one fourth of the original perimeter. TrueFalse
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False the new perimeter is half of the original.
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3 years ago
Y=3x+2<br><br> please help me lolz
Elanso [62]

Answer:

Slope (M): 3

Y-Int: 2

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3 0
2 years ago
A total of 300 pine and maple trees will be planted in a park. There will be 2 pine trees planted for every 3 maple trees plante
mars1129 [50]

Answer:

  120

Step-by-step explanation:

2 of every 5 trees are pine trees.

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5 0
3 years ago
(10
Anni [7]

Given:

The matrix multiplication

\begin{bmatrix}4&5&6\\1&2&3\end{bmatrix}\begin{bmatrix}10\\20\\30\end{bmatrix}

To find:

The order of resulting matrix.

Solution:

We know that, if order of first matrix is m_1\times n_1 and the order of second matrix is m_2\times n_2, then the order of these two matrices is m_1\times n_2.

We have,

\begin{bmatrix}4&5&6\\1&2&3\end{bmatrix}\begin{bmatrix}10\\20\\30\end{bmatrix}

Here, the order of first matrix is 2\times 3 and the order of the second matrix is 3\times 1. So, the order of the second matrix is 2\times 1. It is also written are 2 by 1.

Therefore, the correct option is A.

6 0
3 years ago
Read 2 more answers
An aircraft carrier left Port 35 traveling north five hours before a container ship. The container ship traveled in the opposite
Molodets [167]

Answer:

Aircraft carrier speed = 4.97 km/h

Step-by-step explanation:

Given that the time taken by the aircraft = 5 hours

Let the distance covered = X

Speed = V

Time taken by the ship = 7 hours

Let the distance covered = Y

Speed = 8V

Since it is 8 km/h faster than the aircraft carrier.

Using the speed formula

Speed = distance/time

Distance = speed × time

For the aircraft;

X = 5V

For the ship:

Y = 7 × 8V = 56V

Since they are 303km distance apart,

X + Y = 303

5V + 56V = 303

61V = 303

V = 303/61

V = 4.97 km/h

Aircraft carrier speed = 4.97 km/h

5 0
3 years ago
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