16y^3 + 9x^2y - 54x = 0
16*3y* dy/dx + 9x^2* dy/dx + 18xy - 54 = 0
dy/dx = = (54 - 18xy) / (48y + 9x^2)
I have to go I can do the second part later
4x + 14 = k
Do the opposite of PEMDAS
Isolate the x, subtract 14 from both sides
4x + 14 (-14) = k (-14)
4x = k - 14
divide 4 from both sides
4x/4 = (k-14)/4
x = (k-14)/4 is your answer
hope this helps
Initial velocity = 0 m/s
Acceleration = 9.8 m/s²
Time = 3.1 s
s = ut + 1/2 at²
s = 1/2 x 9.8 x 3.1²
s = 47.1 m
The building is 47.1 meters tall
5 degrees.
hope this helps!
tell me if you need an expaination