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Citrus2011 [14]
3 years ago
6

A rectangle has a length that is 2 greater then its width. The area is 15 square centimeters. what are the dimensions of the rec

tangular?
length =_____ cm

Width=_____ cm​
Mathematics
1 answer:
GaryK [48]3 years ago
3 0

9514 1404 393

Answer:

  • length 5 cm
  • width 3 cm

Step-by-step explanation:

Your knowledge of multiplication facts tells you 3×5 = 15. Your knowledge of addition facts tells you 3+2 = 5. So, the dimensions 3 cm and 5 cm are the width and length of the rectangle, respectively.

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What is the sum of the reciprocal of 1/-13 and the reciprocal of -1/2
murzikaleks [220]

Answer:

-15

Step-by-step explanation:

1/-13

The reciprocal is

1/ 1/-13

Because of the law of indices,

We'll have 1 * -13

= -13.

-1/2

The reciprocal is

1 ÷ -1/2

Because of the law of indices,

We'll have 1 * -2

= -2

Therefore, the sum would be -13 + (-2) which would be equals to -15.

6 0
3 years ago
Solve the given differential equation by using an appropriate substitution. The DE is a Bernoulli equation.
Mama L [17]

Multiplying both sides by y^2 gives

xy^2\dfrac{\mathrm dy}{\mathrm dx}+y^3=1

so that substituting v=y^3 and hence \frac{\mathrm dv}{\mathrm dv}=3y^2\frac{\mathrm dy}{\mathrm dx} gives the linear ODE,

\dfrac x3\dfrac{\mathrm dv}{\mathrm dx}+v=1

Now multiply both sides by 3x^2 to get

x^3\dfrac{\mathrm dv}{\mathrm dx}+3x^2v=3x^2

so that the left side condenses into the derivative of a product.

\dfrac{\mathrm d}{\mathrm dx}[x^3v]=3x^2

Integrate both sides, then solve for v, then for y:

x^3v=\displaystyle\int3x^2\,\mathrm dx

x^3v=x^3+C

v=1+\dfrac C{x^3}

y^3=1+\dfrac C{x^3}

\boxed{y=\sqrt[3]{1+\dfrac C{x^3}}}

6 0
4 years ago
Find the inverse function of c=w+3?
Aneli [31]

Answer:

f^-1(x)=w-3

Step-by-step explanation:

1. switch c with f

f=w+3

2. switch w and f

w=f+3

3. solve for f

f=w-3

4. Switch f with f^-1(x)

f^-1(x)=w-3

3 0
3 years ago
After m months, the height of a plant is 10+3m millimeters. How tall is the plant after eight months? Three years?
Oksanka [162]
Why not start out by writing a linear relationship for the plant height?

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After 8 months, the plant height is h(8) = 10 mm + 3(8) mm, or 34 mm.

After 3 years (36 months), the plant ht. is h(36) = 118 mm.
4 0
4 years ago
What the perimeter of this
olga2289 [7]
D) 142 (i can't make the square root symbol)

/18 = 3/2 
(3/2 + 4/2) x 2 = 14/2
6 0
4 years ago
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