Answer:
a set of two or more equations, each containing two or more variables whose values can simultaneously satisfy both or all the equations in the set, the number of variables being equal to or less than the number of equations in the set.
Step-by-step explanation:
It works because of two properties of equations: Multiplying (or dividing) the expression on each side by the same number does not alter the equation. Adding two equations produces another valid equation: e.g. 2x = x + 10 (x = 10) and x − 3 = 7 (x also = 10).
Answer: x = 1
Step-by-step explanation:
5 ( 2x - 8 ) + 15 = -15 (write the equation)
5 ( 2x - 8 ) = -30 (subtract by 15 on both sides)
2x - 8 = -6 (divide by 5 on both sides)
2x = 2 (add 8 to both sides)
x = 1 (divide by 2 on both sides)
Work: 5√2 + √18
First you must find the largest perfect square in √18:
The perfect square happens to be 9
√18 => 9√2
You must then simplify 9 since it is a perfect square:
9√2 => 3√2
Then you must add both terms together:
5√2 + 3√2 = 8√2
Answer: 8√2 or 8 square root 2
I hope this helps you!
Answer:
C: is a function because each input (x) has exactly one output( y).
Step-by-step explanation:
A function is when one input (x) has exactly one output (y).
A: is not a function because -4 is paired with two different y values.
B: is not a function because -4 is paired with two different y values.
C: is a function because each input (x) has exactly one output( y).
D: is not a function because -1 is paired with two different y values.
b) The surface area is 564.5. Picture below.
4. Three possibilities.
Formula for volume of a cylinder: πr^2h
Formula for volume of sphere: 4/3πr^3
If the radius of the sphere is 1 inch than the volume is: 4.18879 or 4.19 rounded.
I used substitution on this website https://www.omnicalculator.com/math/volume
Just plug in the 4.18879 at the cylinder volume and put in a random number in the radius or height whichever you want then it'll give you the one you left blank. You'll find three possibilities for the radius and height of 4.18879 volume.
