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Pavel [41]
3 years ago
11

Need help ASAP Will Mark, you brainlist

Mathematics
2 answers:
zlopas [31]3 years ago
8 0

Answer:

(4,-1)

Step-by-step explanation:

Yell at me if im wrong.

Tanzania [10]3 years ago
3 0

Answer:

¼

Step-by-step explanation:

Compare the coordinates of two points to find the rate of change.

Using (0,-5) and (4,-6):

Δy/Δx = ((-6)-(-5))/(4-0) = (-1)/4 = -¼

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A number n is negative
Alborosie

Answer:

-n

Step-by-step explanation:

4 0
3 years ago
A contractor combined x tons of a gravel mixture that contained 10 percent gravel G, by weight, with y tons of a mixture that co
White raven [17]

Answer:

The value of x would be \frac{3}{5}y or \frac{3}{8}z

Step-by-step explanation:

Given,

x tons of 10% gravel G mixture is mixed with y ton of 2% gravel G to obtain  5% gravel mixture,

Thus, gravel G in x ton + gravel in y ton = gravel G in the resultant mixture,          

⇒ 0.1x + 0.02y = 0.05(x+y),

0.1x - 0.05x = 0.05y - 0.02y

0.05x = 0.03y

\implies x = \frac{0.03}{0.05}y=\frac{3}{5}y----(1)

Now, resultant mixture is z ton,

i.e. z=x+y

\implies y = z - x

From equation (1),

x=\frac{3}{5}(z-x) = \frac{3}{5}z-\frac{3}{5}x

x+\frac{3}{5}x=\frac{3}{5}z

\frac{8}{5}x=\frac{3}{5}z

x=\frac{3}{8}z

3 0
3 years ago
When mrs. myles gave a test, the scores were normally distributed with a mean of 72 and a standard deviation of 8. this means th
irina [24]
The empirical rule states that in a normal distribution,
68% of data is within 1 std deviation of the mean
95%  of data is within 2 std deviation of the mean
99.7% of data is within 3 std deviation of the mean

In this case 95% of the cases would be within two std deviations of the mean 
    mean - 8         and    mean + 8
     72   - 8 = 64   and    72 + 8 = 80 

then 95% of the scores are between  64% and 80% on the test. 
5 0
3 years ago
Can someone please explain this to me? Thanks!
Makovka662 [10]

Answer:  Choice D

\displaystyle F\ '(x) = 2x\sqrt{1+x^6}\\\\

==========================================================

Explanation:

Let g(t) be the antiderivative of g'(t) = \sqrt{1+t^3}. We don't need to find out what g(t) is exactly.

Recall by the fundamental theorem of calculus, we can say the following:

\displaystyle \int_{a}^{b} g'(t)dt = g(b)-g(a)

This theorem ties together the concepts of integrals and derivatives to show that they are basically inverse operations (more or less).

So,

\displaystyle F(x) = \int_{\pi}^{x^2}\sqrt{1+t^3}dt\\\\ \displaystyle F(x) = \int_{\pi}^{x^2}g'(t)dt\\\\ \displaystyle F(x) = g(x^2) - g(\pi)\\\\

From here, we apply the derivative with respect to x to both sides. Note that the g(\pi) portion is a constant, so g'(\pi) = 0

\displaystyle F(x) = g(x^2) - g(\pi)\\\\ \displaystyle F \ '(x) = \frac{d}{dx}[g(x^2)-g(\pi)]\\\\\displaystyle F\ '(x) = \frac{d}{dx}[g(x^2)] - \frac{d}{dx}[g(\pi)]\\\\ \displaystyle F\ '(x) = \frac{d}{dx}[x^2]*g'(x^2) - g'(\pi) \ \text{ .... chain rule}\\\\

\displaystyle F\ '(x) = 2x*g'(x^2) - 0\\\\ \displaystyle F\ '(x) = 2x*g'(x^2)\\\\ \displaystyle F\ '(x) = 2x\sqrt{1+(x^2)^3}\\\\ \displaystyle F\ '(x) = \boldsymbol{2x\sqrt{1+x^6}}\\\\

Answer is choice D

5 0
2 years ago
Read 2 more answers
Plz help me with this
Andreyy89
The answer would be C
7/9 = 0.77777778
8 0
3 years ago
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