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3 years ago

I’ll give brainliest if u explain how to do those 3 no links plz:)

Mathematics

2 answers:

VikaD [51]3 years ago

5 0

Answer:

#1 answer : 3/16- simplify both sides of the equation to get the variable alone

#2 answer: x=31.91- the x is already alone, add 14.88 to 17.05 to get 31.91

#3 answer: x= 1/3 (0.3 in decimal form with that line thingy on top of the three)-- isolate the variable by dividing both sides

Step-by-step explanation:

seraphim [82]3 years ago

4 0

31.93

u low key cute too

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Jayden and Sheridan both tried to find the missing side of the right triangle. A right triangle is shown. One leg is labeled as

stellarik [79]

Answer:

Sheridan's Work is correct

Step-by-step explanation:

we know that

The lengths side of a right triangle must satisfy the Pythagoras Theorem

$c^{2}=a^{2}+b^{2}$

where

a and b are the legs

c is the hypotenuse (the greater side)

In this problem

Let

$a=7\ cm\\c=13\ cm$

substitute

$13^{2}=7^{2}+b^{2}$

Solve for b

$169=49+b^{2}$

$b^{2}=169-49$

$b^{2}=120$

$b=\sqrt{120}\ cm$

$b=10.95\ cm$

we have that

Jayden's Work

$a^{2}+b^{2}=c^{2}$

$a=7\ cm\\b=13\ cm$

substitute and solve for c

$7^{2}+13^{2}=c^{2}$

$49+169=c^{2}$

$218=c^{2}$

$c=\sqrt{218}\ cm$

$c=14.76\ cm$

Jayden's Work is incorrect, because the missing side is not the hypotenuse of the right triangle

Sheridan's Work

$a^{2}+b^{2}=c^{2}$

$a=7\ cm\\c=13\ cm$

substitute

$7^{2}+b^{2}=13^{2}$

Solve for b

$49+b^{2}=169$

$b^{2}=169-49$

$b^{2}=120$

$b=\sqrt{120}\ cm$

$b=10.95\ cm$

therefore

Sheridan's Work is correct

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3 years ago

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How to see warnings on brainly? I got one, but don't know why. it is not in my notifications.

kirill [66]

Answer:

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

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3 years ago

(8p - 2) (6p+2) help plz

qaws [65]

Answer:

$48p^2+2p-4$

Step-by-step explanation:

We can use the FOIL method to expand two multiplied binomials. It states that $(a+b)(c+d)=ac+bc+ac+bd$ . The FOIL method stands for First(first terms) outer(outer terms) inner(inner terms) last(last terms).

So, we can expand our binomials now!

$(8p-2)(6p+2)=(8p)(6p)-2(6p)+(8p)(2)-2(2)=48p^2-12p+14p-4=\boxed{48p^2+2p-4}$

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The answer is A. y = x + 14

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4 years ago

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