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adell [148]
3 years ago
10

Go Which operation would be completed second in the following expression? 7² -3+9+8 dividend by two

Mathematics
2 answers:
andriy [413]3 years ago
5 0
First step: simplify exponents
second step: 49 -3
but the thing is when it’s both addition and subtraction u just go from left to right
hope it helps
Lera25 [3.4K]3 years ago
5 0

Answer:

Divide

Step-by-step explanation:

Using PEMDAS, the first would be parenthesis, but there are none, so we do not use P. Next is E which is exponents, which would be the first thing completed. Then is M and D which is multiplication and division. The division is used which is "dividend by two" as it's the second thing completed.

Hope this helped.

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Answer:

Proportion of the students recalled more than 15 names is 91.77%.

Step-by-step explanation:

We are given that a researcher was interested in seeing how many names a class of 38 students could remember after playing a name game After playing the name game, the students were asked to recall as many first names of fellow students as possible.

The mean number of names recalled was 19.41 with a standard deviation of 3.17.

<em>Let X = number of names recalled</em>

SO, X ~ N(\mu = 19.41,\sigma^{2} = 3.17^{2})

The z-score probability distribution is given by ;

                  Z = \frac{X-\mu}{\sigma} } } ~ N(0,1)

where, \mu = mean number of names recalled = 19.41

            \sigma = standard deviation = 3.17

The Z-score measures how many standard deviations the measure is away from the mean. After finding the Z-score, we look at the z-score table and find the p-value (area) associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X.

Now, proportion of the students recalled more than 15 names is given by = P(X > 15 names)

     P(X > 15) = P( \frac{X-\mu}{{\sigma} } } > \frac{15-19.41}{3.17}  } ) = P(Z > -1.39)

                                                      = P(Z < 1.39) = 0.9177  {using z table}

<em>Therefore, proportion of the students recalled more than 15 names is </em><em>91.77%.</em>

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