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adell [148]
3 years ago
10

Go Which operation would be completed second in the following expression? 7² -3+9+8 dividend by two

Mathematics
2 answers:
andriy [413]3 years ago
5 0
First step: simplify exponents
second step: 49 -3
but the thing is when it’s both addition and subtraction u just go from left to right
hope it helps
Lera25 [3.4K]3 years ago
5 0

Answer:

Divide

Step-by-step explanation:

Using PEMDAS, the first would be parenthesis, but there are none, so we do not use P. Next is E which is exponents, which would be the first thing completed. Then is M and D which is multiplication and division. The division is used which is "dividend by two" as it's the second thing completed.

Hope this helped.

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lubasha [3.4K]

Answer:

(-9, -5)

Step-by-step explanation:

Ok, so when you move an image to the right, you are moving along the x-axis, and when you move up, you are moving up the y-axis. So if the altered image is (x,y) and the values are (-5, -1), you reverse what has been done to the image. In this case, since we moved to the right 4 units, we know that means we added 4 to x, so we subtract 4 to get -9. And then, for the y-value, because we added 4, we do the opposite, and subtract 4 to get -5. So the pre-image should be (-9, -5)

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A binomial is going to have two terms. =)
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3 years ago
Find the vertex of the function given below.<br><br> y= x2 - 6x +1
Helga [31]

Answer:

V( 3, -8 )

Step-by-step explanation:

Parable equation is of the form:

( x - h )² = 4p*(y - k)

In that expression, vertex has coordinates V ( h, k )

Then all we have to do is transform the given equation

y = x² - 6x + 1       or     x² - 6x  = y - 1          (1)

We can get a  perfect square trinomial in the first member of the equation according to:

x²  -  6x   =   ( x - 3 )²  - 9

(x - 3 )²   = x² - 6x  + 9

By substitution  en equation (1)

( x - 3 )² - 9 = y - 1

( x - 3 )² = y -1 + 9

( x - 3 )² = y + 8

( x - 3 )² = (y + 8 )

Then vertex coordinates are

V( 3 , -8)

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Answer: D

Step-by-step explanation:

It’s really obvious just circle D

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