What is the area of a rectangle that has side lengths of 3/4 yard and 5/6 yard
1 answer:
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Answer:
See below
Step-by-step explanation:
<u>Part A</u>
A vertical stretch takes place when given that
<u>Part B</u>
A vertical compression takes place when given that
<u>Part C</u>
A vertical stretch is different than a horizontal compression:
- In a vertical stretch, the input stays the same, but the output is multiplied by the scale factor
- In a horizontal compression, the output stays the same, but the input is multiplied by the scale factor
<u>Part D</u>
A reflection across the x-axis means that the output, our y-variable, is the opposite sign. This means that all values of must be negative such that
as mentioned in parts A and B. Also, in part C, since our scale factor is negative, the output is the only one being multiplied by the scale factor.
Answer:
m∠CEB is 55°
Step-by-step explanation:
Since ∠ADE = 55°, and ∠ADE is half of ∠ADC because ED bisects ∠ADC. Bisect means to cut in half.
∠ADC = 110° because it is double of ∠ADE.
Since AB║CD and AD║BC, the two sets of parallel lines means this shape is a parallelogram. In parallelograms, <u>opposite angles have equal measures</u>.
∠ADC = ∠CBE = 110°
All quadrilaterals have a sum of angles 360°. Since ∠DCB = ∠BAD and we know two of these other angles are each 110°:
360° - 2(110°) = 2(∠DCB)
∠DCB = 140°/2
∠DCB = ∠BAD = 70°
∠DCB was bisected by EC, which makes each divided part half.
∠DCE = ∠BCE = (1/2)(∠DCB)
∠DCE = ∠BCE = (1/2)(70°)
∠DCE = ∠BCE = 35°
All triangles' angles sum to 180°.
In ΔBCE, ∠BCE = 35° and ∠CBE = 110°.
∠CEB = 180° - (∠BCE + ∠CBE)
∠CEB = 180° - (35° + 110°)
∠CEB = 55°
Therefore m∠CEB is 55°.
Answer:
A. 4.40 square units
Step-by-step explanation:
The triangle is isosceles with base angles of 70°. The a.pex angle will be ...
180° -2(70°) = 40°
The area of a triangle can be computed from two sides and the angle between them as ...
A = (1/2)ab·sin(γ)
A = (1/2)(3.7)(3.7)sin(40°) ≈ 4.40 . . . square units
