The answer is (f o g)(x) = 2x^2 - 13
In order to find a composite function, you take the first letter (in this case f) and use that equation. You then remove the variable and put in the second letter (g).
f(x) = 2x + 1 ----> Remove variable.
f(x) = 2( ) + 1 ----> Insert g(x)
(f o g)(x) = 2(x^2 - 7) + 1 ----> Distribute
(f o g)(x) = 2x^2 - 14 + 1 ----> Simplify
(f o g)(x) = 2x^2 - 13
<u>Answer</u><u>:
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Required integer is -12.
Step-by-step explanation:
Given:
Required number is integer.
Required integer is less than zero
greater than -13.
When number is substracted from -11, result is positive.
To Find:
The integer=?
Solution:
Lets assume required integer = x
As Required integer is less than zero and greater than -13 ,
-13 < x < 0 ------(1)
Also when number is subtracted from -11, result is positive.
=> -11 – x > 0
=> -11 > x -------(2)
So form 1 and 2
-13 < x < -11 that is x is an integer which is less than -11 and greater than -13. There is only one integer between -13 and -11 that is -12.
Hence required integer is -12.
The answer is 8. This is because when you substitute 8 with “a” you then solve the problem to see if it is equal to the answer. -4+8=4... -4+4=0 so that is wrong and -4+O=-4 which is also incorrect.
728x^2y^3 hope this helps
Answer: (b) exactly one plane contains a given line and a point not on the line.
Step-by-step explanation: The basic postulates of geometry are very-well known to all of us. For example-
(i) The intersection of two lines determines a point,
(ii) Two parallel lines give result to a plane,
(iii) A line and a point not on the line determines a plane, etc...
Thus, with the help of the third point, we can easily arrive at the conclusion that a given line and a point not lying on the line is contained in a plane. For example- see the attached figure, AB is a line and P is any point not on the line. They both contained in the plane ABC.
Hence, the correct option is (b).
