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tatuchka [14]
3 years ago
10

Write the equation of the line that passes through the points (-9,2) and (-2,8).

Mathematics
1 answer:
tresset_1 [31]3 years ago
5 0

Answer:

y = 6/7x + 68/7

Step-by-step explanation:

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Can u pls help me with this question ​
Svetach [21]

Answer:

45 cookies

Step-by-step explanation:

Use a unit rate.

With a unit rate, we find the number of cookies that are baked using 1 scoop.

(30 cookies)/(6 scoops) = 5 cookies/scoop

The rate of 30 cookies to 6 scoops is the same as the unit rate of 5 cookies/scoop.

Now we multiply the unit rate by 9 scoops.

9 scoops * 5 cookies/scoop = 45 cookies

Answer: 45 cookies

6 0
2 years ago
Can somebody give me the answer
kobusy [5.1K]
No, mistake at s2, if there was 0x then they shouldn’t have written anything at all because there are 0 x’s!!!
3 0
2 years ago
PLEASE ANSWER ASAP!! <br><br> Explain two different ways to solve 72^2/4
777dan777 [17]

Answer:

Step-by-step explanation:

72^{\frac{2}{4}}=72^{\frac{1}{2}}= \sqrt{2*2*2*3*3}\\\\\\=2*3*\sqrt{2}\\\\=6\sqrt{2}

6 0
2 years ago
Identify the ellipses, represented by equations, whose eccentricities are less than 0.5
ozzi

Answer:

See explanation

Step-by-step explanation:

Hello, we cannot see the ellipse equations.

The eccentric of an ellipse is given by:

e =  \frac{c}{a}

Assuming the equations are:

\frac{ {x}^{2} }{25}  +  \frac{ {y}^{2} }{16}  = 1

Then a²=25 and b²=16

{c}^{2}  =  {a}^{2}  -  {b}^{2}

{c}^{2}  = 25 - 16

{c}^{2}  =  {3}^{2}

c = 3

The eccentricity is:

e =  \frac{3}{5}  = 0.6

If the ellipse has equation,

\frac{ {x}^{2} }{ {5}^{2} }  +  \frac{ {y}^{2} }{ {3}^{2} }  = 1

then the this time, we have a=5 and b=3.

This means that:

{c}^{2}  =  {a}^{2}  -  {b}^{2}

{c}^{2}  =  {5}^{2}  -  {3}^{2}

{c}^{2}  =  {4}^{2}

c = 4

c =  \frac{4}{5}  = 0.8

3 0
3 years ago
Read 2 more answers
Polymer composite materials have gained popularity because they have high strength to weight ratios and are relatively easy and
Brums [2.3K]

Answer:

t=\frac{51.6-48}{\frac{1.1}{\sqrt{10}}}=10.349      

p_v =P(t_9>10.349)=1.34x10^{-6}  

If we compare the p value and the significance level given for example \alpha=0.05 we see that p_v so we can conclude that we reject the null hypothesis, and the the actual mean is significantly higher than 48 MPa at 5% of significance.

Step-by-step explanation:

1) Data given and notation      

\bar X=51.6 represent the sample mean

s=1.1 represent the standard deviation for the sample      

n=10 sample size      

\mu_o =48 represent the value that we want to test    

\alpha=0.05 represent the significance level for the hypothesis test.    

t would represent the statistic (variable of interest)      

p_v represent the p value for the test (variable of interest)  

State the null and alternative hypotheses.      

We need to conduct a hypothesis in order to determine if the mean score is higher than 48, the system of hypothesis would be:      

Null hypothesis:\mu \geq 48      

Alternative hypothesis:\mu > 48      

We don't know the population deviation, so for this case is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:      

t=\frac{\bar X-\mu_o}{\frac{\sigma}{\sqrt{n}}} (1)      

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".  

Calculate the statistic      

We can replace in formula (1) the info given like this:      

t=\frac{51.6-48}{\frac{1.1}{\sqrt{10}}}=10.349      

Calculate the P-value      

First we find the degrees of freedom:

df=n-1=10-1=9

Since is a one-side upper test the p value would be:      

p_v =P(t_9>10.349)=1.34x10^{-6}  

Conclusion      

If we compare the p value and the significance level given for example \alpha=0.05 we see that p_v so we can conclude that we reject the null hypothesis, and the the actual mean is significantly higher than 48 MPa at 5% of significance.        

5 0
3 years ago
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