General equation of parabola: y-k = a(x-h)^2
Here the vertex is at (0,0), so we have y-0 = a(x-0)^2, or y = ax^2
All we have to do now is to find the value of the coefficient a.
(1,2) is on the curve. Therefore, 2 = a(1)^2, or 2 = a(1), or a = 2.
The equation of this parabola is y = 2x^2.
Number 7 is C because all of them are less than 1/2 or 0.50
Answer:
y = -0.2x + 8
Step-by-step explanation:
To write a linear function, calculate the rate of change of the gallon of water leaving the tank and the starting level.
The function will describe the number of gallons over time or (time, gallons).
This means the function has data points (1, 7.8) and (9, 6.2).
Use the rate of change or slope formula to calculate it.
![m = \frac{7.8 - 6.2}{1 - 9} =\frac{1.6}{-8} = -0.2](https://tex.z-dn.net/?f=m%20%3D%20%5Cfrac%7B7.8%20-%206.2%7D%7B1%20-%209%7D%20%3D%5Cfrac%7B1.6%7D%7B-8%7D%20%3D%20-0.2)
This means that for the formula y = mx+b then m = -0.2.
This also means that after losing 0.2 gallons the first hour it was at 7.8. So the starting value is 8 gallons.
The equation is y = -0.2 x + 8.
Answer:
![area = \frac{8}{3}pie ft^2](https://tex.z-dn.net/?f=area%20%3D%20%5Cfrac%7B8%7D%7B3%7Dpie%20ft%5E2)
Step-by-step explanation:
Area of sector is given as θ/360*πr²
Where,
θ = central angel of sector, m < DCE = 60°
r = radius = 4 feet
Area of sector = ![\frac{60}{360}*pie*4^2](https://tex.z-dn.net/?f=%20%5Cfrac%7B60%7D%7B360%7D%2Apie%2A4%5E2)
![area = \frac{1}{6}*pie*16](https://tex.z-dn.net/?f=%20area%20%3D%20%5Cfrac%7B1%7D%7B6%7D%2Apie%2A16)
![area = \frac{1*16}{6}*pie](https://tex.z-dn.net/?f=%20area%20%3D%20%5Cfrac%7B1%2A16%7D%7B6%7D%2Apie)
![area = \frac{16}{6}*pie](https://tex.z-dn.net/?f=%20area%20%3D%20%5Cfrac%7B16%7D%7B6%7D%2Apie)
![area = \frac{8}{3}pie ft^2](https://tex.z-dn.net/?f=area%20%3D%20%5Cfrac%7B8%7D%7B3%7Dpie%20ft%5E2)
Area of the sector = 8/3π ft²
O is the midpoint of Reason: Defintiin of a midpoint