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nikdorinn [45]
3 years ago
11

Emerson practice a game that was on sale for 18% off the sales tax in his country is a present let y represent the original pric

e of the Latin expression that can be used to determine the final cost of the game.
Mathematics
1 answer:
lawyer [7]3 years ago
4 0

Answer: y - 0.18y

Step-by-step explanation:

From the question, Emerson practice a game that was on sale for 18% off the sales tax in his country.

Let y represent the original price of the game. The be used to determine the final cost of the game will be:

We have to subtract the 18% discount from the original price to get the final cost of the game. This will be:

= y - (18% of y)

= y - (18/100 × y)

= y - (0.18 × y)

= y - 0.18y

The final expression is y-0.18y

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Find the center,vertices,foci,and asymptotes of the hyperbola.
bogdanovich [222]

Answer:

The center is (8 , -9)

The vertices are (11 , -9) and (5 , -9)

The foci are (8 , -9 + √58) and (8 , -9 - √58)

The equations of the asymptotes are y = 3/7(x − 8) - 9 , y = -3/7 (x − 8) - 9

Step-by-step explanation:

- The standard form of the equation of a hyperbola with  

  center (h , k) and transverse axis parallel to the y-axis is

  (y - k)²/a² - (x - h)²/b² = 1

- The length of the transverse axis is 2 a  

- The coordinates of the vertices are ( h ± a , k )  

- The length of the conjugate axis is 2 b  

- The coordinates of the co-vertices are ( h , k ± b )

- The coordinates of the foci are (h , k ± c), where c² = a² + b²

- The equations of the asymptotes are y = ± a/b (x − h) + k

* Now lets solve the problem

∵ (y + 9)²/9 - (x - 8)²/49 = 1

∴ h = 8 and k = -9

∴ a² = 9 ⇒ a = ± 3

∴ b² = 49 ⇒ b = ± 7

∵ c² = a² + b²

∴ c² = 9 + 49 = 58

∴ c = ± √58

∵ The center is (h , k)

∴ The center is (8 , -9)

∵ The coordinates of the vertices are ( h ± a , k )

∴ The vertices are (8 + 3 , -9) and (8 - 3 , -9)

∴ The vertices are (11 , -9) and (5 , -9)

∵ The coordinates of the foci are (h , k ± c)

∴ The foci are (8 , -9 + √58) and (8 , -9 - √58)

∵ The equations of the asymptotes are y = ± a/b (x − h) + k

∴ The equations of the asymptotes are y  = 3/7 (x - 8) - 9 and  

   y  = -3/7 (x − 8) - 9

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