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Gelneren [198K]
3 years ago
15

I’m confused on this one

Mathematics
2 answers:
Firdavs [7]3 years ago
5 0

C

This is a rotation followed by a translation.

Zanzabum3 years ago
3 0

This one <em>is</em> confusing. It appears like the right image is the left image translated. But if this is somehow the process, the middle figure indicates its more like a rotation followed by another rotation. This would flip the shape so technically it wouldn't be a translation.

I'd go with choice c, No, rotation followed by rotation.

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Mama L [17]

Answer:

X= 18

CBD= 47

Step-by-step explanation:

3 0
3 years ago
An indoor sport exhibition is coming to the arena. Your supervisor has asked you to help set up a handball pitch and seating are
Sphinxa [80]

Answer:

Perimeter: 174.8 m

Area: 1,394 sq m

Step-by-step explanation:

First, the perimeter.

Before we start, let's calculate the circumference of the half-circles at the ends of the field.

The measurement says 2,000 cm, so let's convert it to 20 m for ease.

Circumference of a circle: πd, where d = diameter.. in our case d = 20 m

Circumference of a 20m diameter circle: 20π = 62.8 m

We have 2 half circles... so the perimeter of each half-circle will be: 31.4 m

We also have 800 cm measurement for the "height" of the seating areas... let's convert that in 8 m

We also need to find out the space between the seating area...  We know the whole rectangular pitch is 40 m, then we have to subtract the width of both seating areas (20 and 15 m)... so the space between them is 5m

So, starting with the upper left corner of the rectangular pitch, and working our way clockwise, we encounter the following lengths:

P = 40 + 31.4 + 8 + 10 + 8 + 5 + 8 + 25 + 8 + 31.4 = 174.8 m

The total perimeter is then of 174.8 m

For the area, we need to calculate the area of all forms:

Large rectangular pitch:

LR = 40 x 20 = 800 sq m

The two half circles, form a circle, so A = πr², where r is the radius, which is half the diameter.

AC = π (10)² = 100 π = 314 sq m

Then the seating areas:

SA1 = 25 x 8 = 200 sq m

SA2 = 10 x 8 - 80 sq m

Then, we add up everything:

TA = LR + AC + SA1 + SA2

TA = 800 + 314 + 200 + 80 = 1,394 sq m

3 0
3 years ago
I need help graphing this
uranmaximum [27]

Answer: y=4/3x-2

Y-Intercept: -2

Slope: 4/3

Step-by-step explanation:

On the Y-Axis put -2 because thats the Y-intercept.

And for slope graph a slope of 4/3

7 0
2 years ago
What is the solution of 3(2x - 1) - 2(3x + 4) = 11x?
Eduardwww [97]

3(2x - 1) - 2(3x + 4) = 11x

  • Distribute 3 inside the parentheses.

6x - 3 - 2(3x + 4) = 11x

  • Distribute 2 inside the parentheses.

6x - 3 - 6x - 8 = 11x

  • Combine like terms.

-11 = 11x

  • Divide both sides by 11.
<h3>x = -1</h3>
6 0
3 years ago
Read 2 more answers
The table below shows school T-shirt sales for the past ten weeks. The school wants to make one more order for the next 30 weeks
Marta_Voda [28]

Answer:

Mean =13, Median=9, Mode =7, Range=43

Step-by-step explanation:

\left\begin{array}{c|cccccccccccc}Month&Sept &Sept& Sep& Oct& Oct &Oct &Oct &Oct &Nov& Nov\\Day&10 &17& 24& 1 &8& 15& 22& 29& 5 &12\\Sales&7 &50 &8& 9& 10& 12 &7& 7 &9& 11\end{array}\right

(1)Mean

Mean =\frac{\text{Sum of all the Sales}}{\text{Number of Sales}}

=\frac{7+50+8+9+10+12+7+7+9+11}{10}\\=\frac{130}{10} \\\bar x =13\\Mean=13

<u>Median</u>

First we arrange the sales in ascending order

7,7,7,8,9,9,10,11,12,50

Since there are two terms in the middle, the Median =(9+9)/2 =9

<u>Mode</u>

The mode is the number of sales with the highest frequency.

Mode =7

<u>Range</u>

Range =Highest Value - Lowest value  =50-7=43

(b)Mean =13, Median=9, Mode =7, Range=43

The Median seems to best represent the ten numbers. this is as a result of the fact that the value of the Mean and range were affected by the outlier number(50).

The School should therefore order T-Shirts in the range of the Median.

3 0
3 years ago
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