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stira [4]
3 years ago
10

Rheology is best described as the study of _______.

Chemistry
1 answer:
Charra [1.4K]3 years ago
3 0

Answer:

its a

Explanation:

edge 2020

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How many moles are in 15.0 g of copper (ii) sulfate?
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<span>The molecular formula for Copper(II) Sulfate is CuSO4. 1 mole is equal to 1 moles Copper(II) Sulfate, or 159.6086 grams.I hope this is right </span>
7 0
4 years ago
Think about a synthetic material that you use every day. How
marysya [2.9K]

explanation: Synthetic fiber or synthetic fibre (in British English; see spelling differences) are fibers made by humans through chemical synthesis, as opposed to natural fibers that are directly derived from living organisms. They are the result of extensive research by scientists to improve upon naturally occurring animal and plant fibers. In general, synthetic fibers are created by extruding fiber-forming materials through spinnerets, forming a fiber. These are called synthetic or artificial fibers. Synthetic fibers are created by a process known as polymerization, which involves combining monomers to make a long chain or polymer. The word polymer comes from a Greek prefix "poly" which means "many" and suffix "mer" which means "single units". (Note: each single unit of a polymer is called a monomer). There are two types of polymerization: linear polymerization and cross-linked polymerization.

4 0
3 years ago
How many grams are in 5.3x10^25 molecules of co2
dem82 [27]

Answer:

3873.15 grams

Explanation:

7 0
3 years ago
A sample containing KBr (M 119&amp;/mol) and KNO3 (M 101 g/mol) was analysed by using the Mohr method, A 1.1250-g sample is diss
djverab [1.8K]

Explanation:

(a)   As we know that relation between normality and volume of two solutions is as follows.

               N_{1}V_{1} = N_{2}V_{2}

As the given data is as follows.

             N_{1} = ?,              N_{2} = 0.050 N

              V_{1} = 20 ml,      V_{2} = 16.25 ml

Therefore, putting the given values into the above formula as follows.

                N_{1}V_{1} = N_{2}V_{2}

                N_{1} \times 20 ml = 0.050 N \times 16.25 ml

                N_{1} = 0.0406 N

Hence, normality of solution A is 0.0406 N.

(b)   As gram equivalent weight of KBr is 119 g/mol.

Formula to calculate normality is as follows.

              Normality = \frac{weight}{gm equi. wt} \times \frac{1000}{V_{ml}}

As volume is 200 ml, normality is 0.0406 N, and gram equi. wt is 119 g/mol. Therefore, putting these values into the above formula as follows.

          Normality = \frac{weight}{gm equi. wt} \times \frac{1000}{V_{ml}}      

          0.0406 N  = \frac{weight}{119 g/mol} \times \frac{1000}{200 ml}

              weight = 0.9668 g

As 0.9668 g of KBr is present in 1.1250 g sample. Hence, weight percentage will be calculated as follows.

                   Weight % of KBr = \frac{0.9668 g}{1.1250 g}

                                               = 85.94%

Thus, we can conclude that C% w/w of KBr in the original sample is 85.94%.

8 0
3 years ago
The _______ bonds between the carboxyl and amine groups of the amino acids cause the straight chain to fold and twist, forming t
Assoli18 [71]

Answer:

Secondary: H-bond between carboxyl and amine groups of amino acid cause straight chain to fold and twist forming

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3 years ago
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